Which means she ran 4160 miles long
if this isn't the answer you wanted, please be more precise
Answer with explanation:
A: Treasury Bond: In treasury bond interest is paid till that duration until the bond completely matures. When the period of bond gets over, Actual amount or Par Amount is Returned.
⇒A Saving Instrument.
B. C D
Compact Disc. A type of device that can store data, that is Nanotechnology is used to store more than 500 MB of data.
C: Saving Account
In saving Account, you can deposit and withdraw money at any time ,any day, with the evolution of new technology.
D: Checking Account
Same with the checking account,you can withdraw and deposit money any time on a day.
→Option A, C and D are , types of account , related with currency that is money, but option B, is term related to data.
Option B: →C D is not a Saving Instrument.
Answer:
it il fill 600, 8 ounce bottles
Step-by-step explanation:
4,800 divided 8 = 600
the total is 600 bottles
i hope this helps, have a great day. And good luck!
<span> SO in total, Emily and Sarah had a total of 80
dollars in which Emily had twice as much as Sarah.
Let’s solve to find out how much their Money is.
=> Since the ratio of the given data is 2:1, 2 + 1 =3, so let’s divide 80 by
3
=> 80 / 3 = 26.667 ,
=> Emily has twice as this.
=> 26.667 * 2 = 53.33
=> Sarah has 26.67
Now, Sarah spent 1/3 of her money
=> 26.67 / 3 = 8.89 – her remaining money
Emily spent 17 dollars of her money
=> 53.33 – 17 = 36.33</span>
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.