2 years ago

PLEASE HELP I WILL GIVE BRAINLESIST

Mathematics

1 answer:

kaheart [24]2 years ago

4 0

A is your answer

let me know if you have any questions

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x-3=6

Add + 3 to both sides

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x=9

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$4^x-10\cdot2^x+16=0\Rightarrow(2^2)^x-10\cdot2^x+16=0\Rightarrow(2^x)^2-10\cdot2^x+16=0$

$subtitute\ 2^x=t > 0\\\\t^2-10t+16=0\\t^2-2t-8t+16=0\\t(t-2)-8(t-2)=0\\(t-2)(t-8)=0\iff t-2=0\ or\ t-8=0\\\\t=2\ or\ t=8\\\\t=2^1\ or\ t=2^3\\\\therefore\ 2^x=2^1\ or\ 2^x=2^3\\\\Answer:\boxed{x=1\ or\ x=3}$

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3 years ago

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