Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q
You need to add the second number and the answer to get your answer
A. 2
B.6
D.5
F.4
G. 3
Answer:
Expanded Notation Form:
97,367 =
90,000
+ 7,000
+ 300
+ 60
+ 7
Expanded Factors Form:
97,367 =
9 × 10,000
+ 7 × 1,000
+ 3 × 100
+ 6 × 10
+ 7 × 1
Expanded Exponential Form:
97,367 =
9 × 104
+ 7 × 103
+ 3 × 102
+ 6 × 101
+ 7 × 100
Answer:
The acceleration of the car will be 400 m/s².
Step-by-step explanation:
The acceleration of the car can be found using Newton second law:
Where:
F: is the net force = 200 N
m: is the mass = 500 g
a: is the acceleration =?
Then, the acceleration will be:
Therefore, the acceleration of the car will be 400 m/s².
I hope it helps you!