Step 1;calculate the molar mass of NH4N03
molar mass of different element
N=14
H=1
O=16
therefore molar mass of NH4NO3 is 14+4+14+48= 80g/mol
step 2:find the molar mass of N present in NH4NO3
That is 14+14 =28g/mol
the mass is therefore
{(28g/mol/80g/mol) x 89g} =31.15g
342.14 g/mol
Molar mass of Al= 26.98
Molar mass of S=32.06
Molar mass of O=16.00
(26.98)2+(32.06+(16.00×4))3=342.14
Answer:
Explanation:
Total pressure of the mixture = 300 mm Hg
equation of reaction
C₇ H₁₆(g) + 11 O₂ (g) → 7 CO₂(g) + 8 H₂O(g)
partial pressure of heptane = mole fraction heptane × total pressure = 1 / 12 × 300 mm Hg = 25 mm Hg
partial pressure of oxygen = mole fraction oxygen × total pressure = 11 / 12 × 300 mm Hg = 275 mm Hg
After the reaction
total number of mole before the reaction = 12
total number of mole after the reaction = 15
temperature and volume did not change
if 12 to 300 mm Hg
15 will be 15 × 300 / 12 = 375 mm Hg
partial pressure of water vapor = mole fraction of water vapor × 375 mm Hg = 8 / 15 × 375 mm Hg = 200 mm Hg
Answer:
Death rates, Birth rates, and immigration rates
Explanation:
You could lower the heat so that the molecules move slower