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3 years ago

During photosynthesis, plants transform

Chemistry

1 answer:

attashe74 [19]3 years ago

6 0

During Photosynthesis , Plants Transforms Light Energy Into Chemical Energy .

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A super conductor performs best at

Anastaziya [24]

A superconductor performs best at very cold temperatures.

4 0

3 years ago

How many ml of concentrated hydrochloric acid would be required to make 1 L of a 0.2 M solution? Assume that concentrated hydroc

fgiga [73]

Answer: The volume of concentrated hydrochloric acid required is 16.53 mL

Explanation:

To calculate the volume of concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution

We are given:

Conversion factor: 1 L = 1000 mL

$M_1=12.1M\\V_1=?mL\\M_2=0.2M\\V_2=1L=1000mL$

Putting values in above equation, we get:

$12.1\times V_1=0.2\times 1000\\\\V_1=16.53mL$

Hence, the volume of concentrated hydrochloric acid required is 16.53 mL

3 0

3 years ago

Which of the following samples had the lowest average kinetic energy?

Aleksandr [31]

Answer:

B. 10 mL of Cabr2(aq) at 35 degrees celsius

Explanation:

The colder something is the more the atoms are compressed together; atoms can't move as much. 35 degrees is the warmest option, so it makes the most sense.

6 0

2 years ago

Read 2 more answers

URGENT!!! What is the concentration in moles per litre of a solution that contains 7.68 g of H2SO4 in 150.0 mL of water?

hichkok12 [17]

Answer: 0.5225 mcl/l

Explanation:

5 0

3 years ago

Identify the correct coefificients to balance it -C3H8+O2 to -CO2 +-H2O

Iteru [2.4K]

Answer:

${\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

Explanation:

${\rm ?\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}$ .

Among the four species in this reaction, $\rm C_3H_8$ is species with the largest number of atoms per molecule. Assume that the coefficient of this compound is $1$ .

${\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}$ .

Number of atoms on the left-hand side of the reaction:

$\rm C$ : $1 \times 3 = 3$ .
$\rm H$ : $1 \times 8 = 8$ .
$\rm O$ : not found yet.

By the conservation of atoms, the number of atoms on the right-hand side of the reaction should match those on the left-hand side. In this reaction, $\rm CO_2$ is the only product with carbon atoms, whereas $\rm H_2O$ is the only product with hydrogen atoms. These $3$ carbon atoms and $8$ hydrogen atoms would correspond to:

$3 / 1 = 3$ $\rm CO_2$ molecules, and
$8 / 2 = 4$ $\rm H_2O$ molecules.

${\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

Number of atoms on the right-hand side of the reaction:

$\rm C$ : $3 \times 1 = 3$ .
$\rm H$ : $4 \times 2 = 8$ .
$\rm O$ : $3 \times 2 + 4 \times 1 = 10$ .

The number of $\rm O$ atoms on the left-hand side should match those on the right-hand side. In this reaction, $\rm O_2$ is the only reactant with $\rm O\!$ atoms. These $10$ $\rm \! O$ atoms would correspond to:

$5$ $\rm O_2$ molecules.

${\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

5 0

2 years ago