Answer:
it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma
Is there a picture or something that i can see what is the smallest in mass i do not have enough info
Missing question: volume of <span>solution on the left is 10 mL.
V</span>₁(solution) = 10 Ml.
c₁(solution) = 0.2 M.<span>
V</span>₂(solution)
= ?.<span>
c</span>₂(solution)
= 0.04 M.<span>
c</span>₁ -
original concentration of the solution, before it gets diluted.<span>
c</span>₂
- final concentration of the solution, after dilution.<span>
V</span>₁
- <span>volume to
be diluted.
V</span>₂ - <span>final volume after
dilution.
c</span>₁ · V₁ = c₂ · V₂<span>.
</span>10 mL · 0.2 M = 0.04 M · V₂.
V₂(solution) = 10 mL · 0.2 M ÷ 0.04 M.
V₂(solution) = 50 mL.<span>
</span>
Answer:
The freezing point of chloroform (CHCl₃) in presence of benzene = - 64.252 °C.
Explanation:
- We can solve this problem using the relation:
ΔTf = Kf.m,
Where, ΔTf is the elevation of freezing point,
Kf is the freezing point depression constant <em>(Kf of chloroform = 4.7 °C/m)</em>,
m is the molality of the solution.
- We can get the molality of benzene from the relation:
m = (mass / molar mass) solute (benzene) x (1000 / mass of solvent (CHCl₃))
m = (1.25 g / 78.11 g/mol) x (1000 / 100.0 g) = 0.160 m.
ΔTf = Kf.m = (4.70 °C/m) (0.160 m) = 0.752 °C.
∴ The freezing point in presence of benzene = The freezing point of pure CHCl₃ - ΔTf = - 63.50 °C – 0.752 °C = - 64.252 °C.
