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Fittoniya [83]
3 years ago
12

How much Cu-64 (half-life about 12 hours) would remain from a 2 mg sample after 12 hours?​

Chemistry
2 answers:
Bogdan [553]3 years ago
7 0

Answer:

i beleive it is  A if not here a cookie online cookie also dont forget to wear your mask kiddos

Explanation:

Sindrei [870]3 years ago
6 0

Answer:

1 mg is correct via a p e x

Explanation:

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Why is it important for scientists to review and repeat the work of other scientists
guapka [62]

Answer:

Accuracy

Explanation:

It is important for scientists to review the work of other scientists, so they can be sure there are no mistakes or lack of judgement. They repeat to compare results to make hypotheses.

3 0
2 years ago
A compound has the empirical formula . a 256-ml flask, at 373 k and 750. torr, contains 0.527 g of the gaseous compound. give th
CaHeK987 [17]
<span>Answer: From the ideal gas law, MM=mRTPV; where MM = molecular mass; m = mass; P = pressure in atmospheres; V= volume in litres; R = gas constant with appropriate units. So, 0.800â‹…gĂ—0.0821â‹…Lâ‹…atmâ‹…Kâ’1â‹…molâ’1Ă—373â‹…K0.256â‹…LĂ—0.987â‹…atm = 97.0 gâ‹…molâ’1. nĂ—(12.01+1.01+2Ă—35.45)â‹…gâ‹…molâ’1 = 97.0â‹…gâ‹…molâ’1. Clearly, n = 1. And molecular formula = C2H2Cl2. I seem to recall (but can't be bothered to look up) that vinylidene chloride, H2C=C(Cl)2 is a low boiling point gas, whereas the 1,2 dichloro species is a volatile liquid. At any rate we have supplied the molecular formula as required.</span>
4 0
3 years ago
1. Determine the amount concentration of calcium ions and acetate ions in a 0.80 mol/L
PIT_PIT [208]

Since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

<h3>What is concentration?</h3>

The term concentration has to do with the amount of substance in solution. The concentration can be measured in several units. Generally, concentration is expressed in molarity, molality, mass concentration units or percentage.

Now we are asked to find the amount concentration of calcium ions and acetate ions in a 0.80 mol/L solution of calcium acetate. The formula of calcium acetate is Ca(CH3COO)2.

Thus;

Ca(CH3COO)2(aq)  ----> Ca^2+(aq) + 2CH3COO^-(aq)

It then follows that since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

Learn more about concentration:brainly.com/question/10725862

#SPJ1

6 0
1 year ago
Balance the following equations by inserting the proper coefficients.
Montano1993 [528]
1212. 1212. 1323........

6 0
3 years ago
Read 2 more answers
Help me please I need to pass my exam
Troyanec [42]

Answer:

I think it is 1115 kJ but I don't see the answer

Explanation:

8 0
3 years ago
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