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LenaWriter [7]
3 years ago
6

How many grams of N are in 89.0 g of NH4NO3

Chemistry
1 answer:
yarga [219]3 years ago
8 0
Step 1;calculate  the  molar  mass  of   NH4N03 
molar  mass  of different  element
N=14
H=1
O=16
therefore  molar  mass  of  NH4NO3   is 14+4+14+48= 80g/mol
step 2:find the  molar mass of N  present  in  NH4NO3
   That  is  14+14 =28g/mol
the mass  is  therefore
{(28g/mol/80g/mol) x 89g} =31.15g
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3 years ago
If 0.500 mol of NaN3 react what mass I'm grams of nitrogen would result
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3 years ago
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 mole of c
yuradex [85]

Answer:

Theoretical moles of V are 1.6 moles

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The theoretical yield of a reaction is defined as the amount of product you would make if all of the limiting reactant was converted into product.

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Based on the reaction, 1 mol of V2O5 needs 5 moles of Ca for a complete reaction. As there are just 4 moles, <em>limiting reactant is Ca.</em> As there are produced 2 moles of V per 5mol of Ca, Theoretical moles of V are:

4 moles of Ca × (2mol V / 5Ca) = <em>1.6 moles of V</em>

<em></em>

I hope it helps!

5 0
2 years ago
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fomenos

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3 years ago
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