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2 years ago

Which statement is supported by this scenario?

Physics

2 answers:

Temka [501]2 years ago

6 0

Answer:

For Yanni, the speed of the ball is 15 m/s, and for the quarterback, the speed of the ball is 8 m/s.

Explanation:

likoan [24]2 years ago

4 0

Answer:

For Yanni, the speed of the ball is 23 m/s, and for the quarterback, the speed of the ball is 15 m/s.

Explanation:

Right on edge 2021

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Please help me .finish this paper

Evgesh-ka [11]

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7 0

3 years ago

A projectile is fired with an initial velocity of 450 feet per second at an angle of 70° with the horizontal.

pav-90 [236]

<h2>After 26.28 seconds projectile returns 26.28 seconds.</h2>

Explanation:

Initial velocity = 450 ft/s = 137.16 m/s

Angle, θ = 70°

Consider the vertical motion of projectile,

When the projectile return to the ground we have

Displacement, s = 0 m

Acceleration, a = -9.81 m/s²

Initial velocity, u = 137.16 x sin70 = 128.89 m/s

Substituting in s = ut + 0.5 at²

s = ut + 0.5 at²

0 = 128.89 x t + 0.5 x (-9.81) x t²

t² - 26.28 t = 0

t ( t- 26.28) = 0

t = 0 s or t = 26.28 s

After 26.28 seconds projectile returns 26.28 seconds.

5 0

3 years ago

From a set of graphed data the slope of the best fit line is found to be 1.35 m/s and the slope of the worst fit line is 1.29m/s

Svetradugi [14.3K]

Solution:

Let the slope of the best fit line be represented by ' $m_{best}$ '

and the slope of the worst fit line be represented by ' $m_{worst}$ '

Given that:

$m_{best}$ = 1.35 m/s

$m_{worst}$ = 1.29 m/s

Then the uncertainity in the slope of the line is given by the formula:

$\Delta m = \frac{m_{best}-m_{worst}}{2}$ (1)

Substituting values in eqn (1), we get

$\Delta m = \frac{1.35 - 1.29}{2}$ = 0.03 m/s

8 0

3 years ago

A passenger on a Ferris wheel moves in a vertical circle at a constant speed. Are the forces on her balanced?

vovikov84 [41]

C. The force is a constant change, because her position on the Ferris wheel will constantly change. I believe this is the answer, but use sources to double check. I might use different vocab. then your teachers.

6 0

3 years ago

You pull a block of mass m across across a frictionless table with a constant force. you also pull with an equal constant force

KiRa [710]

For any mass m:

a = F/m
v = √2*F/m*s = √2F/sm = k/√m
Momentum = mv = k√m
Energy = 1/ mv² = 1/2 m.k²/m = 1/2k²

SO
Both will have same energy
The larger mass will have greater momentum

4 0

3 years ago