Answer:
Rows and Periods
Elements are listed in order of increasing atomic number from left to right. Each row of the periodic table is called a period and each column of the periodic table is called a group (or family).
Explanation:
Option C
Both Technician A and Technician B is correct
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Explanation:</u></h3>
The pressure differential valve is the equipment that warns you if you leak one of your brake circuits. After draining and refilling some brake system pressure differential switch may be actuated and an indication light may be illuminated. If the indication light sojourns sparked after draining the valve piston may demand to be re-centered. If the pressure is replaced to the brake line and your brakes appear to be running accurately over, then the reset button operated.
The common practical method to re-center the piston is to fix the failure, drain the system and then generate a pressure loss opposite what moved the piston in the first place. Each type has a unique kind of re-centering technique.
Answer:
a) 633.39 J
b) 0.28
Explanation:
a)The kinetic energy of the player = 
Work done by friction = energy change of the player
= 
= 633.9 J
b) Assuming the frictional force stays constant,
Work done by friction = Frictional force×distance
Frictional force = kinetic friction(μ)×normal reaction
Normal reaction = weight = mass×gravitational acceleration ( g=10m/s2 )
Combining these equations
633.9 = F×3.4 ⇒ F = 186.44 N
F = μmg ⇒ μ = F/mg
= 186.44/670
= 0.28
Answer:
9.4 m
Explanation:
We can use a moving frame of reference with the same speed as the car. From this frame of reference the car doesn't move. The origin is at the back of the car, the positive X axis points back and the positive Y axis points up.
If the ballon is launched at 9.7 m/s at 39 degrees of elevation.
Vx0 = 9.7 * cos(39) = 7.5 m/s
Vy0 = 9.7 * sin(39) = 6.1 m/s
If we ignore air drag, the baloon will be subject only to the acceleration of gravity. We can use the equation of position under constant acceleration.
Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2
Y0 = 0
a = -9.81 m/s^2
It will fall when Y(t) = 0
0 = 6.1 * t - 4.9 * t^2
0 = t * (6.1 - 4.9 * t)
t1 = 0 (this is when the balloon was launched)
0 = 6.1 - 4.9 * t2
4.9 * t2 = 6.1
t2 = 6.1 / 4.9 = 1.25 s
The distance from the car will be the horizonta distance it travelled in that time
X(t) = X0 + Vx0 * t
X(1.25) = 7.5 * 1.25 = 9.4 m
Explanation:
to overcome the repulsion between the protons in the nuclei that join
