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Dmitriy789 [7]
4 years ago
13

Standing on the roof of a (42.0+A) m tall building, you throw a ball straight up with an initial speed of (14.5+B) m/s. If the b

all misses the building on the way down, how long will it take from you threw the ball until it lands on the ground below? Give your answer in seconds and round the answer to three significant figures.
Physics
1 answer:
RSB [31]4 years ago
4 0
First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:

2as = v² - u²

Because the final velocity v is 0 in such cases

s = -u²/2a; because both u and a are downwards, the negative sign cancels

s = 14.5² / 2*9.81
s = 10.72 meters

Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m

We will use the formula 
s = ut + 0.5at²

to find the time taken with the initial velocity u = 0.

55.72 = 0.5 * 9.81 * t²

t = 3.37 seconds
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In class we described the tidal forces that are responsible for raising and lowering thewater level near the shore of the ocean.
Sloan [31]

The newton's law of universal gravitation used to describe how a particle attracts every other particle in the universe.

The equation is given by,

F= G\frac{m_1 m_2}{r_2}

Where,

F= Gravitational force

m_1, m_2 = masses of the objects

r= is the distance between the center of their masses

G= Gravitational constant

For our problem we have defined that,

M_m = 7.24*10^{22}kg (mass of the moon)

d= 3.84*10^8 km (distance Earth-moon)

G= 6.671*10^{-11}Nm^2/kg^2

M=Mass of a person

We have then,

F_m = M\frac{6.67*10^-11*7.34*10^22}{3.84*10^8}

F_m = M*3.320*10^{-5} N

In the other hand we have the force on m-mass due to earth

F_E= MG = M*9.8N

Ratio is given by

\frac{F_m}{F_E} = {M*3.320*10^{-5}}{9.8} = 3.387*10^{-6}

B) Suppose there is a group of young people surfing in the moonlight. They are directly under the moon. At this time the moon exerts its gravitational effect of the earth that causes the tide to rise. Around 6 hours later, when the earth has moved a quarter of the moon, the force on that point decreases, so the tide drops. However, after another 6 hours, people return and experience the same process. In this case the moon is not above them, but on the other side. This is because the moon having an orbit on the earth, generates an external force, similar to the previous one, but the earth reacts in the opposite way. It is like going in a car and turning it, all people will tend to get out of it, because a centrifugal force is experienced.

7 0
4 years ago
A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?
GalinKa [24]

Answer:

The electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

Explanation:

Given

Radius,\ r = 0.03m\\Charge,\ q =7.6\µC

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε = 8.8542 * 10^{-12}

Substitute ε = 8.8542 * 10^{-12} and q =7.6\µC; The formula becomes

Ф = \frac{7.6\µC}{8.8542 * 10^{-12}}

Ф = \frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}

Ф = \frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}

Ф = \frac{7.6}{8.8542} *10^{12-6}}

Ф = 0.85834970974 *10^{12-6}}

Ф = 0.85834970974 *10^{6}}

Ф = 8.5834970974 *10^{5}}

Ф = 8.58 *10^{5} \frac{Nm^2}{C}

Hence, the electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

7 0
3 years ago
What force is needed to give a mass of 20kg an acceleration of 5.0m/s?
Marysya12 [62]

Answer:

a=5

m= 20

F= m×a

20×5

=100N

5 0
3 years ago
0. A 5-kg block of ice is at a temperature of -27 °C. How much heat must be added to the ice to produce 5 kg of liquid water wit
stellarik [79]

Answer:

Q = 2687130 J

Explanation:

m = mass of block of ice = 5 kg

T_{i} = Initial temperature of ice block = - 27 °C

T_{f} = final temperature of water = 35 °C

c_{i} = specific heat of ice = 2108 J/(Kg °C)

L = Latent heat of fusion of ice = 334000 J/kg

c_{w} = specific heat of water = 4186 J/(Kg °C)

Heat added is given as

Q = m c_{i}(0 - T_{i})+ mL + m c_{w}(T_{f} - 0)

Q = (5) (2108)(0 - (-27))+ (5)(334000) + (5) (4186)(35 - 0)

Q = 2687130 J

8 0
3 years ago
Utility companies charge by the kilowatt-hour. The number of kilowatt-hours used equals the number of kilowatts multiplied by th
Dmitry [639]

Answer:

t = 3 minutes

Explanation:

Given that,

Power of fan, P = 50 W

Energy used, E = 1 kWh

We know that,

Energy = Power/time

As, 50 watts = 0.05 kilowatts

So,

t=\dfrac{P}{E}\\\\t=\dfrac{0.05\ kW}{1\ kWh}\\\\t=0.05\ h

or

t = 3 min

So, the required time is equal to 3 minutes.

3 0
3 years ago
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