It is purely called the Atomic Mass
Answer:
![\boxed{\text{136 g}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B136%20g%7D%7D)
Explanation:
We will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 44.01 180.16
6CO₂ + 6H₂O ⟶ C₆H₁₂O₆ + 6O₂
m/g: 200
1. Moles of CO₂
![\text{Moles of CO}_{2} = \text{200 g CO}_{2} \times \dfrac{\text{1 mol CO}_{2}}{\text{ 44.01g CO}_{2}} = \text{4.54 mol CO}_{2}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20CO%7D_%7B2%7D%20%3D%20%5Ctext%7B200%20g%20CO%7D_%7B2%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20CO%7D_%7B2%7D%7D%7B%5Ctext%7B%2044.01g%20CO%7D_%7B2%7D%7D%20%3D%20%5Ctext%7B4.54%20mol%20CO%7D_%7B2%7D)
2. Moles of C₆H₁₂O₆
The molar ratio is 1 mol C₆H₁₂O₆:6 mol CO₂
![\text{Moles of C$_{6}$H$_{12}$O}_{6} =\text{4.54 mol CO}_{2} \times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{6 mol CO}_{2}} = \text{0.757 mol C$_{6}$H$_{12}$O}_{6}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%20%3D%5Ctext%7B4.54%20mol%20CO%7D_%7B2%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%7D%7B%5Ctext%7B6%20mol%20CO%7D_%7B2%7D%7D%20%3D%20%5Ctext%7B0.757%20mol%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D)
3. Mass of C₆H₁₂O₆
![\text{Mass of C$_{6}$H$_{12}$O}_{6} = \text{0.757 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} =\textbf{136 g C$_{6}$H$_{12}$O}_{6}\\\\\text{The plants can create }\boxed{\textbf{136 g C$_{6}$H$_{12}$O}_{6}}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%20%3D%20%5Ctext%7B0.757%20mol%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B180.16%20g%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%7D%7B%5Ctext%7B1%20mol%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%7D%20%3D%5Ctextbf%7B136%20g%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%5C%5C%5C%5C%5Ctext%7BThe%20plants%20can%20create%20%7D%5Cboxed%7B%5Ctextbf%7B136%20g%20C%24_%7B6%7D%24H%24_%7B12%7D%24O%7D_%7B6%7D%7D)
Answer:
Trial Y, because the volume of product formed per unit time is lower than Trial X.
Explanation:
The rate of reaction depends on the amount of reactants present. Now remember that the rate of reaction is either measured as the rate of disappearance of reactants or as the rate of appearance of products.
In this case, we consider the rate of reaction as the rate of appearance of products per unit time. Reading off from the graph, it is quite easy to observe that the volume of product formed per unit time for trial Y is lower than that of Trial X. Since we have earlier agreed that the rate of reaction depends on the initial concentration of reactants. It follows that the reason for the lower volume of product formed per unit time for trial Y is because of a lower initial concentration of the reactants in trial Y. Hence the answer.
Answer:
C.faste-moving lava flows and explosion of cinder
Major Plates
Africa Plate
Antarctic Plate
Indo-Australian Plate
Australian Plate
Eurasian Plate
North American Plate
South American Plate
<span>Pacific Plate
Minor Plates
There are dozens of smaller plates, the seven largest of which are:
</span>Arabian Plate
Caribbean Plate
Juan de Fuca Plate
Cocos Plate
Nazca Plate
Philippine Sea Plate
<span>Scotia Plate</span>