Answer:
5
Step-by-step explanation:
I do not fully understand what the question is because you didn't ask a question, so I just found the difference between the 2 scores, which would be a positive 5.
Or if its asking which score is greater it would be Giovanna because her score was closer to zero than Vera's score.
Answer:
a) summation of p(x)/n ie. (0.1712+...+0.0051)/6=0.16675
b)1
c).var=summation (x-mean) squared /n ie (0.1712-0.16675)squared +...+(0.0051-0.16675)squared/n=0.027351948
SD =square root of variance =0.16538
Step-by-step explanation:
Answer: The scale factor is 4
Step-by-step explanation:
We know that the pyramids are similar. The volume of one of these pyramids is 13,824 cubic feet and the volume of the other one is 216 cubic feet. Then:

By Similar solids theorem, if two similar solids have a scale factor of
, then corresponding volumes have a ratio of 
Then:

Knowing this, we can find the scale factor. This is:
![\frac{13,824}{216}=\frac{a^3}{b^3}\\\\\frac{13,824}{216}=(\frac{a}{b})^3\\\\\frac{a}{b}=\sqrt[3]{\frac{13,824}{216}}\\\\scale\ factor=\frac{a}{b}=4](https://tex.z-dn.net/?f=%5Cfrac%7B13%2C824%7D%7B216%7D%3D%5Cfrac%7Ba%5E3%7D%7Bb%5E3%7D%5C%5C%5C%5C%5Cfrac%7B13%2C824%7D%7B216%7D%3D%28%5Cfrac%7Ba%7D%7Bb%7D%29%5E3%5C%5C%5C%5C%5Cfrac%7Ba%7D%7Bb%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B13%2C824%7D%7B216%7D%7D%5C%5C%5C%5Cscale%5C%20factor%3D%5Cfrac%7Ba%7D%7Bb%7D%3D4)
Answer:
6x10=60
Step-by-step explanation
each person is giving $10 to see a movie, you multiple it
Answer:

Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

Solve for <em>r: </em>
<em />
<em />
Simplify. Thus:

Finally, add:

We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:
