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Aleksandr-060686 [28]

3 years ago

12

What are the coordinates of point H? On a coordinate plane, point H is 1.5 units to the left and 3 units up. (Negative 3, 1 and

one-half) (Negative 1 and one-half, 3) (1 and one-half, 3) (3, negative 1 and one-half) Mark this and return

2 answers:

Dima020 [189]3 years ago

7 0

Answer:

b

Step-by-step explanaton

ik okay

Vesna [10]3 years ago

5 0

Answer:

Option 2 (B)

Step-by-step explanation:

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There goes my hopes for Virtuoso rank....

Tpy6a [65]

Y = x^2 + 10x - 171
y = (x - 9)(x + 19)

x - 9= 0 x + 19 = 0
x = 9 x = -19

Answer B covers all requirements... the factored form is
y= (x + 19)(x - 9)
and the zeros are -19 and 9

3 0

3 years ago

What is the equation for the line?

antoniya [11.8K]

Answer:

y=-4x+5

Step-by-step explanation:

the line goes down 4 for every 1 that x changes. the line crosses the y axis at 5.

(this might not be accurate, I can't really see if the line is on the exact point or not)

6 0

4 years ago

Read 2 more answers

The table shows the speeds of several runners on a track team. What is the speed, in feet per minute, of the fastest runner?

Ipatiy [6.2K]

Where is the table? I would love to help!

3 0

3 years ago

Find the coordinates of the point(s on the curve 2y=10?x2 that are closest to the origin

sergey [27]

No it far 10 is way out there

4 0

3 years ago

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

6 0

3 years ago