x = 3,-1, multiplicity of 2.
Therefore, it is 4-degree polynomials. (considering that x = 3,-1,2,2)
We just convert these x-values into x-intercept form and convert again in standard form by multiplying.
(x-3)(x+1)(x-2)²
(x²-2x-3)(x²-4x+4)
(x⁴-4x³+4x²-2x³+8x²-8x-3x²+12x-12)
Thus the answer is x⁴-6x³+9x²+4x-12
Answer:
3x + 4
Step-by-step explanation:
We have a product of 3 and x. That's rewritten as 3x. We then have 4 more, so we add 4. That gives us the final answer of: 3x+4. (It is 1-4x for the third one). ( The fourth one) The sum of seven and the quotient of a number x and eight
Here, x be the number.
" quotient of a number x and eight" translated to x/8
Sum means '+'
"sum of seven and the quotient of a number x and eight" translated to 7+ x/8 +56+x/8
then; the given statement is 56+x/8
⇒
Therefore, the given statement is 56+x/8
Answer:
square with 8 sides
Step-by-step explanation:
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Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).
<u>Point-slope form</u>:-
Substitute 1 for y₁, 2 for m, and 0 for x₁:-
So we conclude that Option B is correct.
<h3>Good luck.</h3>
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Answer:
Step-by-step explanation:
I think you have the question incomplete, and that this is the complete question
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
To do this, we can start my mirroring the equation.
x² + y² = (x + y)² - 2xy,
This helps us break down the power from 4 to 2, so that we have
(sin²a)² + (cos²a)² = (sin²a + cos²a) ² - 2(sin²a) (cos²a)
Recall from identity that
Sin²Φ + cos²Φ = 1, so therefore
(sin²a)² + (cos²a)² = 1² - 2(sin²a) (cos²a)
On expanding the power and the brackets, we find that we have the equation proved.
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
