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lukranit [14]
3 years ago
15

A regression equation that predicts the price of homes in thousands of dollars is t = 24.6 + 0.055x1 - 3.6x2, where x2 is a dumm

y variable that represents whether the house in on a busy street or not. Here x2 = 1 means the house is on a busy street and x2 = 0 means it is not. Based on this information, which of the following statements is true? And why?
a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

b) On average, homes that are on busy streets are worth $3.6 more than homes that are not on busy streets.

c) On average, homes that are on busy streets are worth $3.6 less than homes that are not on busy streets.

d) On average, homes that are on busy streets are worth $3600 more than homes that are not on busy streets.
Mathematics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

Step-by-step explanation:

For the same home (x1 is the same), x2 = 1 if it is on a busy street and x2 = 0 if it is not on a busy street. If x2 = 1, the value of 't' decreases by 3.6 when compared to the value of 't' for x2=0. Since 't' is given in thousands of dollars, when a home is on a busy street, its value decreases by 3.6 thousand dollars.

t(x1, 0)= 24.6 + 0.055x1\\t(x1, 1) = 24.6 + 0.055x1 - 3.6\\t(x1, 1) = t(x1, 0) - 3.6

Therefore, the answer is a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

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The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

y = ax^2 + bx + c

The given quadratic equation is 24x^2 + 2x = 15

Let's rearrange the equation

24x^2 + 2x = 15\\24x^2 + 2x - 15 = 0

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The equation or formula of quadratic formula is given as

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We can substitute the values into the equation and solve

y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}

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brainly.com/question/8649555

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Step-by-step explanation:

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