Someone please help!!!

Mathematics

1 answer:

ycow [4]2 years ago

8 0

Answer:

C: -1,2

Step-by-step explanation:

The solution is where both line intersect and touch each other.

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HELP MAYDAYYY!!!<br> What is the value of x?

cricket20 [7]

I think Its 6.............

5 0

2 years ago

Plzzzzz help tomorrow is my maths test

maria [59]

16 ) GO...

a) 5487 × ( 65 + 35 ) = 5487 × 100 = 548700

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b) 647 × ( 112 - 12 ) = 647 × 100 = 64700

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c) 502 × 1,008 = ( 500 + 2 ) ( 1,000 + 8 ) = 500,000 + 4,000 + 2,000 + 16 = 506,016

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17 ) Go...

a) 585 × 16 × 625 = 585 × 4 × 4 × 25 × 25 = 585 × 4 × 25 × 4 × 25 = 585 × 100 × 100 = 5,850,000

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b) 147 × 50 × 2 = 147 × 100 = 14,700

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18) Go...

look : 1729 = ( 1400 + 329 ) = 7 × 200 + 7 × 47 = 7 ( 200 + 47 ) = 7 × 247 = 7 × 13 × 19

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19) Go...

look : 96 = 16 × 6 = 2⁴ × 2 × 3 = 2⁵ × 3

Thus ;

the factors are : ( 1 , 2 , 3 , 4 , 6 , 8 , 12 , 16 , 24 , 32 , 48 , 96 )

3 0

2 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$