Answer Question Pls? I need Help!!

Mathematics

1 answer:

QveST [7]3 years ago

8 0

Answer:

option D

Step-by-step explanation:

Take the two through which the lines passes.

Let it be ( -5 , 0) and ( 0 , -3)

Step 1 : Find slope, m

$Slope,m = \frac{y_2 -y_1}{x_2 - x_1}$

$= \frac{-3-0}{0--5} = \frac{-3}{5}$

Step 2 : Find the equation

$(y - y_ 1) = m( x - x_1)\\\\( y - 0) = \frac{-3}{5} (x --5) \\\\y = -\frac{3}{5}( x + 5 ) \\\\y = -\frac{3}{5}x - 3$

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Given the function <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-2x-5" id="TexFormula1" title="f(x)=x^2-2x-5" alt="f(x)=x^2

juin [17]

Answer:

- 1

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ - 5, 6 ] , then

f(b) = f(6) = 6² - 2(6) - 5 = 36 - 12 - 5 = 19

f(a) = f(- 5) = (- 5)² - 2(- 5) - 5 = 25 + 10 - 5 = 30

Then

average rate of change = $\frac{19-30}{6-(-5)}$ = $\frac{-11}{6+5}$ = $\frac{-11}{11}$ = - 1

6 0

3 years ago

Please help! - - - - -

Jlenok [28]

The answer has to be in y-intercept form. Which is y=mx+b and b can also be neg. y=mx-b. The m is your slope and b is your y-intercept. So A’s slope counting from 3 on the y axis to 1 on the x-axis which is down 2 over 1 so it will be -2/1. And your y intercept is 3. The equation is y=-2x+3. For B its the same thing but no graph. Remember that slope is RISE over RUN. So since the number is on the bottom of the line the rise is 4 and the run is 1. So in this case 10 is your y-intercept. Which means you equation is y=4x+10.