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*40 IF YOU ANSWER CORRECTLY & ADDED BRAINIEST*

Vikentia [17]

Answer:

1. B

2. C

Explanation:

1. There are 15 electrons which means that the element is phosphorus. We know it is in the excited state because an electron from the second ring has moved to the third one, typically it would be 2 - 8 - 5.

2. An element with 3 valence electrons will be 3 spaces from the left side of the periodic table. Sodium is 1, Magnesium is 2, Aluminium is 3, and Silicon is 4. Noble gasses on the right have all 8.

6 0

3 years ago

NH3 + HCl---> NH4Cl What is the Chemical reaction

KATRIN_1 [288]

Answer:

A combination reaction

Explanation:

The chemical reaction between ammonia and hydrochloric acid as shown below:

NH₃ + HCl → NH₄Cl

is a combination reaction.

In a combination reaction, two compounds combines together to give one compound.

A combination reaction is also known as a synthesis reaction.

A single product forms from tow or more reactants.

The driving force for such reaction is the large and negative heat of formation of the product.

5 0

3 years ago

Write the net ionic equation for any precipitation reaction that may be predicted when aqueous solutions of calcium iodide and c

Hitman42 [59]

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

$3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)$

Ionic form of the above equation follows:

$3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)$

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)$