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Stolb23 [73]
3 years ago
9

Which balanced equation represents a chemical change? A) H2O() + energy → H2O(g) B) 2H2O() + energy → 2H2(g) + O2(g) C) H2O() →

H2O(s) + energy D) H2O(g) → H2O() + energy
Chemistry
1 answer:
IgorC [24]3 years ago
5 0
Although your question is incomplete, I believe 'B' is the answer, as the Oxygen separates from the Hydrogen
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What is the concentration of a solution that is 0.25 moles of HCL added to 3.00L of water?
Lina20 [59]

Answer: 0.08 M

Explanation:

\text{molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}\\\\\text{molarity}=\frac{0.25}{3.00}\\\\\text{molarity}=\boxed{0.08 \text{ M}}

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2 years ago
Why does secondary succession usually occur more rapidly than primary succession.
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3 years ago
8. A sample of potassium chlorate (KCIO,) was heated in a test tube and decomposed 2KC?(s) 302 (g) + 2KCIO, (s) The oxygen was c
dangina [55]

Answer:

Partial pressure of O_{2} in the gas was 733 torr and mass of KClO_{3} in the sample was 2.12 g.

Explanation:

a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of O_{2})

Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.

So, partial pressure of O_{2}= (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr

b) Lets assume that O_{2} behaves ideally. Hence-

                                            PV=nRT

where P is pressure of O_{2}, V is volume of O_{2} , n is number of moles of O_{2} , R is gas constant and T is temperature in kelvin

here P = 733 torr = (733\times 0.001316)atm = 0.9646 atm

        V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K

   So, n=\frac{PV}{RT}

                   = \frac{(0.9646 atm)\times (0.65 L)}{(0.082 L.atm/(mol.K))\times (295 K)}

                   = 0.0259 moles

As 3 moles of O_{2} are produced from 2 moles of KClO_{3} therefore 0.0259 moles of O_{2} are produced from (\frac{2\times 0.0259}{3}) moles or 0.0173 moles of KClO_{3}.

Molar mass of KClO_{3}= 122.55 g

So mass of KClO_{3} in sample = (0.0173\times 122.55)g

                                                                    = 2.12 g

7 0
3 years ago
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           pKa  = -log Ka
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3 0
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4vir4ik [10]

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8 0
3 years ago
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