Answer:
B) It will increase.
Explanation:
Solubility tends to increase with an increase in temperature
Answer:A
Explanation:
Your muscular system is at work
Answer:
Hint As we know that the concept of mole is mainly to calculate the entities at the microscopic level that is ions, particles, molecules, electrons or atoms etc. It is found that mole is having the symbol mol.
Complete Step by step solution:
- As we are being provided with the information that there is 15 grams of lithium. As we know that the molar mass of lithium is 6.94 g/mol.
- As we know that mole is the amount of substance that has entities as there are atoms exactly in 12 g of carbon isotope. We should note that the number of entities in one mole is important because it is called the Avogadro constant. The numeric value of this constant is 6.022×1023.
- Firstly we will write the given mass as:
156.022×1023
- Now, we can find the number of moles by the formula of moles that is given mass of the substance divided by the molar mass of the substance.
moles=given massmolar mass⟹156.022×10236.94⟹15×6.946.022×1023⟹17.28×10−23moles
- Hence, we can conclude that there are 17.28×1023 moles in 15 grams of lithium.
Note:
- If we want to calculate the number of moles of an individual entity, like say A, that is dissolved in a solution of an entity say B (A+B), then we can do so by using the concept of mole fraction. The formula of mole fraction is given as moles of a substance divided by the total number of moles.
- We should not forget to write the unit after solving the solution. Explanation:
Answer:
2.38x10²³ atoms oxygen
Explanation:
To solve this question we need to convert the mass of sand to moles using its molar mass (Molar mass SiO₂ = 60.08g/mol). Twice these moles are the moles of Oxygen and using Avogadro's number we can find the amount of atoms of Oxygen in the mixture:
<em>Moles SiO₂:</em>
11.87g * (1mol / 60.08g) = 0.1976moles SiO₂
<em>Moles Oxygen:</em>
0.1976moles SiO₂* 2 = 0.3951moles oxygen
<em>Atoms oxygen:</em>
0.3951moles oxygen * (6.022x10²³atoms / 1mol O₂) =
<h3>2.38x10²³ atoms oxygen</h3>