2) Increasing the rate of the reverse reaction will cause a shift to the left.
Hopefully, If it is wrong my full apologies.
OR IF THATS WRONG, TRY THIS
a - Increasing the rate of the forward reaction will cause equilibrium to be more product-favored (i.e. shift to the right, not the left)
Reaction of
Acyl Halides with
Grignard reagent results in the formation of
Ketones in first step. While in second step reaction of Grignard reagent with Ketones results in the formation of
Tertiary Alcohols.
If you want to
stop the reaction at
Ketone stage then you are required to use another
mild reactive organometallic compound. In our case we will use Organocuprates.
Organocuprates are also known as Gilman Reagents. These reagents does not add to ketones, aldehydes and esters but they can add to acid halides to produce Ketones.
values of the quantum numbers: -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
location of the electron: In the 7th energy level away from the nucleus.
Explanation:
From the description of the problem, the magnetic number is given is as -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and the electron is located in the 7th energy level away from the nucleus. Basically, the problem is testing for the understanding of the principal quantum numbers which gives the location of electrons and the magnetic quantum number that shows the spatial orientation of the orbitals.
The orbital designation of the describe electron is 7d
- Magnetic quantum number is limited by the azimuthal quantum number which is the quantum number describing the possible shapes. The azimuthal is given as L= n-1. "n" is the principal quantum number which is 7. Therefore L is 6 and the magnetic quantum numbers are -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
- The position of the electron is given by the principal quantum number which represents the main energy level in which the orbital is located or the average distance from the nucleus. Here it is 7.
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Answer:
500N/m²
Explanation:
The Pressure can be calculated using the formula:
P = F/A
Where;
F = force (N)
A = Area (m²)
Based on the information provided in the question, F = 30N, A = 0.06m²
P = F/A
P = 30/0.06
P = 500N/m²
1) Chemical reaction 1: 4Cu + O₂ → 2Cu₂O.
n(Cu) = 88,8 ÷ 63,55.
n(Cu) = 1,4.
n(O) = 11,2 ÷ 16.
n(O) = 0,7.
n(Cu) : n(O) = 1,4 : 0,7.
n(Cu) : n(O) = 2 : 1.
Compound is Cu₂O.
2) Chemical reaction 2: 2Cu + O₂ → 2CuO.
n(Cu) = 79,9 ÷ 63,55.
n(Cu) = 1,257.
n(O) = 20,1 ÷ 16.
n(O) = 1,257.
n(Cu) : n(O) = 1,257 : 1,257.
n(Cu) : n(O) = 1 : 1.
Compound is CuO.
