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nikdorinn [45]
3 years ago
9

Find the value of x , this like similar right triangles and geometric means and stuff

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

16

Step-by-step explanation:

We can calculate the value of x using Euclidean theorem

15^2 = 9 × (x+9)

225 = 81 + 9x subtract 81 from both sides

144 = 9x divide both sides by 9

16 = x

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A chicken casserole recipe serves 12
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Answer:

4.5 cups of spinach

Step-by-step explanation:

we know that

The recipe serves 12  people and calls for 3 cups of  spinach

so

using proportion

Find out how many  cups of spinach should you use, to serve 18 people

\frac{12}{3}\ \frac{people}{cups} =\frac{18}{x}\ \frac{people}{cups}\\\\x=18(3)/12\\\\x=4.5\ cups

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Vinvika [58]

Answer: A

Step-by-step explanation:

6 0
3 years ago
(Sec. 8.4) In a sample of 165 students at an Australian university that introduced the use of plagiarism-detection software in a
marusya05 [52]

Answer:

z=\frac{0.667 -0.5}{\sqrt{\frac{0.5(1-0.5)}{165}}}=4.29  

The p value for this case is given by:

p_v =P(z>4.29)=8.93x10^{-6}  

Since the p value is lower than the significance level we have enough evidence to conclude that the true proportion is significantly higher than 0.5 at 5% of significance.

Step-by-step explanation:

Information given

n=165 represent the random sample selected

55 represent the students indicated a belief that such software unfairly targets students

X =165-55= 110 represent students who NOT belief that such software unfairly targets students

\hat p=\frac{110}{165}=0.667 estimated proportion of  students who NOT belief that such software unfairly targets students

p_o=0.5 is the value that we want to check

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to check if the majority of students at the university do not believe that it unfairly targets them, and the system of hypothesis are:

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

After replace we got:

z=\frac{0.667 -0.5}{\sqrt{\frac{0.5(1-0.5)}{165}}}=4.29  

The p value for this case is given by:

p_v =P(z>4.29)=8.93x10^{-6}  

Since the p value is lower than the significance level we have enough evidence to conclude that the true proportion is significantly higher than 0.5 at 5% of significance.

7 0
3 years ago
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