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VashaNatasha [74]
3 years ago
10

Help me, it will mean a lot if u do :)

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
7 0
Tangent must be 90degree so
90-48=42degreeXZU
skelet666 [1.2K]3 years ago
6 0

Answer: 57 degrees

Step-by-step explanation:

Angle ZXY = Angle YZV = 75 degrees (Alternate segment theorem)

Since angles on a straight line add upto 180 degrees:

Angle UZX = 180 - ( 75 + 48) = 57 degrees

Note: 75 is Angle YZV and 48 is Angle XZY

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What is the x-coordinate of the solution for the system of equations? {y−x=910+2x=−2y Enter your answer in the box. x =
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Step-by-step explanation:

y−x=9 ⇒ y=x+9

10+2x=−2y

5+x= -y  ====== replacing y with x+9

5+x= -x-9

2x= -14

x= -7

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Which point is a distance of 5 units from the point (1, 9)? A. (6, 8) B. (2, 4) C. (3, 3) D. (5, 6)
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Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an
lyudmila [28]
<h2>Answer:</h2>

Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°


<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°


So the components can be found as follows:

F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf


So the components of the resultant force can be found by adding each component of the individual forces as follows:

R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf


Finally, the magnitude and direction of the resultant force is:

Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees

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