Question

Pls answer quick it's gr 9 academic math lol

Answer 1

Hi there!

Error 1

$(3^3+3^2)^2\\= (3^5)^2$

The student added the exponents of 3³ and 3² and wrote 3⁵. This rule can only be applied to exponents with the same base that are being multiplied. 3³ and 3² were being added, not multiplied, so this rule can't be applied.

Error 2

$(3^5)^2\\= 3^7$

When a power has a power, we multiply them, not add. Here is the correct way of doing it:

$(3^5)^2\\= 3^5^*^2\\= 3^1^0$

Error 3

$3^7\\= 21$

The student multiplied 3 and 7 to get 21, but 3⁷ actually means 3 multiplied by itself 7 times. The correct answer for this part would be 2187.

I hope this helps!

Answer 2

Answer:

1. (3^3 + 3^2)^2 actually equals (27 + 9)^2

which is the first mistake

2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7

3. 3^7 DOES NOT EQUAL 21

Step-by-step explanation:

when you add powered numbers together, it does not multiply it, as your example:

1. (3^3 + 3^2)^2 actually equals (27 + 9)^2

which is the first mistake

2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7

3. 3^7 DOES NOT EQUAL 21