All categories

3 years ago

Circles and angles/arcs could someone help me with this geometry question please?

Mathematics

1 answer:

Elden [556K]3 years ago

3 0

9514 1404 393

Answer:

arc AB = 60°
arc BC = 78°
arc EF = 40°
angle AFB = 30°

Step-by-step explanation:

The relevant relations are ...

the measures of an arc and its central angle are the same
the sum of the arcs of a circle is 360°
the measure of an inscribed angle is half the measure of the arc it intercepts

Arc AB has the measure of central angle AOB, 60°.

Arc EF has double the measure of inscribed angle EAF, so is 40°.

Arc BC completes the circle, so has measure ...

arc BC = 360° -arc FA -arc AB -arc CE -arc EF

arc BC = 360° -140° -60° -42° -40°

arc BC = 78°

Angle AFB is half the measure of arc AB, so is 60°/2 = 30°.

You might be interested in

If A = {1, 2, 3, 4} and B = {4, 5, 6}, find A ∪ B.

kiruha [24]

Answer:

{ 1,2,3,4,5,6}

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP ME . how can the converse of the Pythagorean theorem help you determine whether the roped off area is in the shape o

trapecia [35]

Step-by-step explanation:

From the Pythagorean theorem we have:

$a^2+b^2=c^2$ <em>subtract b² from both sides</em>

$a^2=c^2-b^2\to a=\sqrt{c^2-b^2}$

Same:

$b=\sqrt{c^2-a^2}$

4 0

3 years ago

Can i have your credit card information

Mekhanik [1.2K]

Answer:

Sorry,I don't have credit card ...Hope get it in future

7 0

3 years ago

Read 2 more answers

Match each statement in the proof with the correct reason.

Svetach [21]

Answer:

area is equal to base times height

5 0

3 years ago

The figure is made up of a cylinder and a sphere which has been cut in half. The radius of each half sphere is 5 mm. What is

alexgriva [62]

<h2>Answer:</h2>

<em>Rounded to the nearest hundredth the volume of the composite figure is:</em>

<em>1308 33 cubic millimeters</em>

<h2>Explanation:</h2>

Hello! I wrote the complete question in a comment above. The volume of a cylinder is defined as:

$V_{c}=\pi r^2 h \\ \\ r:radius \\ \\ h:height$

While the volume of half a sphere is:

$V_{hs}=\frac{2}{3}\pi r^3$

Since we have 2 half spheres, then the volume of these is the same as the volume of a sphere:

$V_{s}=\frac{4}{3}\pi r^3$

Then, the composite figure is:

$V=\pi r^2 h +\frac{4}{3}\pi r^3 \\ \\ V=\pi r^2(h+\frac{4}{3}r)$

The radius of the cylinder is the same of the radius of each half sphere. So:

$r=5mm \\ \\ h=10mm \\ \\ \\ V=(3.14) (5)^2((10)+\frac{4}{3}(5)) \\ \\ V=25(3.14)(10+\frac{20}{3}) \\ \\ \boxed{V\approx 1308.33mm^3}$

7 0

3 years ago