The best approach to this is to use the law of cosine which is stated as
c2 = a2 + b2 â’ 2ab cos(C)
distance a=176.27; distance b=222.34; angle C=38.59; distance c is the missing value.
Hence c²=176.27²+222.34² -2*176.27*222.34cos38.59°= 138.71 miles
The first one is 2x-3y/2
The second one is 1/x+2
The third one is (2x-5y)/(2x+5y)
The fourth one is x^2/z^2
67 percent is your answer
Answer:
The cost of an adult ticket is $12.50
Step-by-step explanation:
The given information are;
The cost of two adult tickets and three children tickets = $43.00
The cost of one adult ticket and one child ticket = $18.50
Whereby the cost of an adult ticket is represented by <em>x</em> and the cost of a child's ticket is represented by <em>y</em>, we get the following two simultaneous equations;
2·x + 3·y = 43.00...(1)
x + y = 18.5...(2)
(ii) Multiplying equation (2) by 2 and subtracting the result from equation (1) gives;
2·x + 3·y - 2×(x + y) = 43 - 2×18.5 = 6
2·x - 2·x + 3·y - 2·y = 0 + y = 6
∴ y = 6
The cost of each the children ticket = $6.00
From equation (2), where y = 6, we get;
x + y = 18.5
∴ x + 6 = 18.5
x = 18.5 - 6 = 12.5
The cost of an adult ticket, x = $12.50.
