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horsena [70]
3 years ago
7

A graph titled velocity versus time has horizontal axis time (seconds) and vertical axis velocity (meters per second). A line ha

s 5 straight segments. Line segment A runs from 0 seconds 0 meters per second to 1 seconds 30 meters per second. Then segment B runs to 3 seconds 30 meters per second. Then an unlabeled segment runs to 4 seconds 40 meters per second. Then an unlabeled segment runs to 5 seconds 40 meters per second. Then segment C runs to 6 seconds 10 meters per second. Then segment D runs to 7 seconds 10 meters per second. Then an unlabeled segment runs to 8 seconds 40 meters per second. Then an unlabeled segment runs to 9 seconds 40 meters per second. Then segment E runs to 10 seconds 20 meters per second. What is the acceleration of the car at segment C? 30 m/s2 –30 m/s2 40 m/s2 –40 m/s2.
Mathematics
2 answers:
prisoha [69]3 years ago
5 0

Answer:

-30m/s

Step-by-step explanation:

Acceleration is the change in velocity with respect to the time. The acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

Given information-

Segment A runs from 0 seconds 0 meters per second to 1 seconds 30 meters per second.

Segment B runs to 3 seconds 30 meters per second.

Segment C runs to 6 seconds 10 meters per second.

Segment D runs to 7 seconds 10 meters per second.

Segment E runs to 10 seconds 20 meters per second.

Acceleration

Acceleration is the change in velocity with respect to the time. Acceleration of a vector quantity which means it has both magnitude and the direction. It can be given as,

Here  denotes the time and  denotes the velocity of the body.

Acceleration at segment C,

Thus the acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

Learn more about the acceleration here;

brainly.com/question/2437624

AnnyKZ [126]3 years ago
4 0

Acceleration is the change in velocity with respect to the time. The acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

<h3>Given information-</h3>

Segment A runs from 0 seconds 0 meters per second to 1 seconds 30 meters per second.

Segment B runs to 3 seconds 30 meters per second.

Segment C runs to 6 seconds 10 meters per second.

Segment D runs to 7 seconds 10 meters per second.

Segment E runs to 10 seconds 20 meters per second.

<h3>Acceleration</h3>

Acceleration is the change in velocity with respect to the time. Acceleration of a vector quantity which means it has both magnitude and the direction. It can be given as,

a=\dfrac{\Delta v}{\Delta t}

Here t denotes the time and v denotes the velocity of the body.

Acceleration at segment C,

a_c=\dfrac{10-40}{6-5}

a_c=-30

Thus the acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

Learn more about the acceleration here;

brainly.com/question/2437624

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loris [4]

Answer:

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Step-by-step explanation:

According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (<em>x</em> - <em>a</em>), then the remainder of the operation will be given by P(a).

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2 years ago
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
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p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
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Now plug x=10 into our original profit function in order to find our maximum profit:
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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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