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horsena [70]
3 years ago
7

A graph titled velocity versus time has horizontal axis time (seconds) and vertical axis velocity (meters per second). A line ha

s 5 straight segments. Line segment A runs from 0 seconds 0 meters per second to 1 seconds 30 meters per second. Then segment B runs to 3 seconds 30 meters per second. Then an unlabeled segment runs to 4 seconds 40 meters per second. Then an unlabeled segment runs to 5 seconds 40 meters per second. Then segment C runs to 6 seconds 10 meters per second. Then segment D runs to 7 seconds 10 meters per second. Then an unlabeled segment runs to 8 seconds 40 meters per second. Then an unlabeled segment runs to 9 seconds 40 meters per second. Then segment E runs to 10 seconds 20 meters per second. What is the acceleration of the car at segment C? 30 m/s2 –30 m/s2 40 m/s2 –40 m/s2.
Mathematics
2 answers:
prisoha [69]3 years ago
5 0

Answer:

-30m/s

Step-by-step explanation:

Acceleration is the change in velocity with respect to the time. The acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

Given information-

Segment A runs from 0 seconds 0 meters per second to 1 seconds 30 meters per second.

Segment B runs to 3 seconds 30 meters per second.

Segment C runs to 6 seconds 10 meters per second.

Segment D runs to 7 seconds 10 meters per second.

Segment E runs to 10 seconds 20 meters per second.

Acceleration

Acceleration is the change in velocity with respect to the time. Acceleration of a vector quantity which means it has both magnitude and the direction. It can be given as,

Here  denotes the time and  denotes the velocity of the body.

Acceleration at segment C,

Thus the acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

Learn more about the acceleration here;

brainly.com/question/2437624

AnnyKZ [126]3 years ago
4 0

Acceleration is the change in velocity with respect to the time. The acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

<h3>Given information-</h3>

Segment A runs from 0 seconds 0 meters per second to 1 seconds 30 meters per second.

Segment B runs to 3 seconds 30 meters per second.

Segment C runs to 6 seconds 10 meters per second.

Segment D runs to 7 seconds 10 meters per second.

Segment E runs to 10 seconds 20 meters per second.

<h3>Acceleration</h3>

Acceleration is the change in velocity with respect to the time. Acceleration of a vector quantity which means it has both magnitude and the direction. It can be given as,

a=\dfrac{\Delta v}{\Delta t}

Here t denotes the time and v denotes the velocity of the body.

Acceleration at segment C,

a_c=\dfrac{10-40}{6-5}

a_c=-30

Thus the acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.

Learn more about the acceleration here;

brainly.com/question/2437624

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Suppose a triangle has two sides of length 2 and 3 and that angle between these two sides is 60 degrees. What is the length of t
Arturiano [62]

Answer:

Apply cosine rule:

c²=b²+a²-2ba cosC

C= pi/3 = 180/3 = 60 degrees

cosine 60 deg = 0.5

c²=2²+3²-[2×2×3×0.5]

c²=7

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Step-by-step explanation:

6 0
3 years ago
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4(5x+25)
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10(2x+10)
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Before we can make the mashed potatoes, we need to boil some water. The water starts out at room temperature, 70° F, and increas
Karolina [17]

Answer:

Part a) y=50t+70

Part b) t=2.84\ min

Step-by-step explanation:

Part a) Create a linear equation

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we know that

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In this problem we have

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The y-intercept is

b=70\° F

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y=50t+70

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6 0
3 years ago
Which expressions are equivalent to \dfrac{2^5}{6^5}
DerKrebs [107]

We have been given an expression \frac{2^5}{6^5}. We are asked to choose the expressions, which are equivalent to our given expression.

Using exponent property \frac{1}{a^n}=a^{-n}, we can rewrite our given expression as:

\frac{2^5}{6^5}=2^5\cdot 6^{-5}

Upon looking at our given choices, we can see that option D is the correct choice.

Let us simplify our given expression.

\frac{2^5}{6^5}=\frac{2^5}{(2\cdot 3)^5}

\frac{2^5}{6^5}=\frac{2^5}{2^5\cdot 3^5}

Upon cancelling out 2^5 from numerator and denominator, we will get:

\frac{2^5}{6^5}=\frac{1}{3^5}

Using exponent property \frac{1}{a^n}=a^{-n}, we will get:

\frac{1}{3^5}=3^{-5}

Therefore, option B is a correct choice as well.

3 0
4 years ago
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