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2 years ago

Whoever awser correct I will give you Brainly

Chemistry

1 answer:

vivado [14]2 years ago

7 0

Answer:

Option A.

2Na + 2H2O —> 2NaOH + H2

Explanation:

To know which option is correct, we shall do a head count of the number of atoms present on both side to see which of them is balanced. This is illustrated below below:

For Option A:

2Na + 2H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

4 H >>>>>>>>>>>> 4 H

2 O >>>>>>>>>>>> 2 O

Thus, the above equation is balanced.

For Option B:

2Na + 2H2O —> NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 3 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

For Option C:

2Na + H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

2 H >>>>>>>>>>>> 4 H

1 O >>>>>>>>>>>> 2 O

Thus, the above equation is not balanced.

For Option D:

Na + 2H2O —> NaOH + 2H2

Reactant >>>>>>> Product

1 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 5 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

From the illustrations made above, only option A is balanced.

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1 year ago

Problem PageQuestion

mixer [17]

1) The mass of 1 mole of virus is $5.4\cdot 10^6 kg$

2) There are 5.6 moles of viruses in an oil tanker

Explanation:

One mole of a substance is the amount of that substance containing a number of particles equal to the Avogadro number:

$N_A = 6.022\cdot 10^{23}$

This means that 1 mole of this virus should contain a number of virus particles equal to $N_A$ .

We know that the mass of 1 virus particle is

$m=9.0\cdot 10^{-12} mg = 9.0\cdot 10^{-18} kg$

Therefore, the mass of 1 moles of viruses is equal to the mass of a single virus particle multiplied by the number of virus particles in one mole, $N_A$ :

$M=mN_A = (9.0\cdot 10^{-18})(6.022\cdot 10^{-23})=5.4\cdot 10^6 kg$

In this problem, we have that the mass of the oil tanker is

$M_o = 3.0\cdot 10^7 kg$

We also know that the mass of one mole of virus is

$M=5.4\cdot 10^6 kg$

Therefore, we can find how many moles of viruses have a mass equal to the mass of the oil tanker by dividing the mass of the oil tanker by the mass of 1 mole of virus particles.

Mathematically, this is done by the following operation:

$N=\frac{M_O}{M}=\frac{3.0\cdot 10^7 kg}{5.4\cdot 10^6 kg}=5.6$