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faust18 [17]
3 years ago
7

Point J (-4, -6) and point K (4, 4) are located on a coordinate grid. Which measurement is closest to the distance between point

J and point K in units?
Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

The points are sqrt(164) or 2sqrt(41) units apart.

Explanation:

You didn't provide the options in your question. But to find the distance, you need to use the distance formula.

d=sqrt((y2-y1)^2 + (x2-x1)^2)

d is the distance, and (x1, y1) and (x2, y2) are the points.

Use point J (-4,-6) for (x1,y1) and point K (4,4) for (x2, y2).

d=sqrt((4-(-6))^2 + (4-(-4))^2)

 =sqrt(10^2 + 8^2)

 =sqrt(100+64)

 =sqrt(164)=2sqrt(41)

You can compare this to the answer options and find the closest. Hope I could help! :)

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6)
Rashid [163]

Answer:

Larger rocket: 36 kiloliters

smaller rocket: 24 kiloliters

Step-by-step explanation:

Lets assign the letters: "L" to the number of kiloliters the "Larger" rocket gets, and "S" to the number of kiloliters that the "Smaller" rocket gets.

We can create two equations from the words given in the problem:

First equation: <em>A total of 60 kiloliters is to be used for "L" plus "S"</em>:

which gives us: L+S=60

Next equation comes from the words: "<em>The smaller rocket receives 12 kiloliters less than the larger rocket</em>"

which gives us: S=L-12

Now we can use this last equation to replace for the "S" unknown in the first equation (and thus reducing the problem to one equation with one unknown (L), that one can easily solve):

L+S=60\\L+(L-12)=60\\2L-12=60\\2L=60+12\\2L=72\\L=\frac{72}{2}\\ L=36

Therefore the amount of fuel that the larger rocket gets is 36 kiloliters.

And using the equation  "S = L - 12" we get: S=36-12=24

Which tells us that the smaller rocket gets 24 kiloliters of fuel.

3 0
3 years ago
The area of a rectangular playground enclosure at francis lewis hw is 500 square meters. the lenght of the playground is 5 meter
Alex Ar [27]
A=L*W
L=W+5
A=(W+5)W
500=W²+5W
W²+5W-500=0

W=(-5+/-√(25+4*500))/2=(-5+/-√2025)/2=(-5+/-45)/2
we are going to take only positive value, so W=(-5+45)/2=20
L=W+5=20+5=25
W=20,
L=25

7 0
4 years ago
The length of a rectangle is 2 centimeters less than three times its width. Its area is 21 square centimeters. Find the dimensio
saveliy_v [14]

Area = length x width

Area = 21 square cm

Width = x

Length = 3x + 2

21 = 3x+ 2 * x

21 = 3x ^2 + 2x

Subtract 21 from both sides:

3x^2 + 2x -21 = 0

Use the quadratic formula to solve for x:

-2 +/- sqrt(2^2-4*3(-21))/(2*3)

X = 7/3 and -3

A dimension can’t be a negative value so x needs to be 7/3

Width = x = 7/3 = 2 1/3 cm

Length = 3(7/3) + 2 = 9 cm

Check: 9 x 2 1/3 = 21

Dimensions: width 2 1/3 cm length 9 cm

4 0
3 years ago
Read 2 more answers
Factor the polynomial: x(5x-8)-2(5x-8)
sertanlavr [38]
<span>x(5x-8)-2(5x-8) =(5x-8)(x-2)
Answer is </span><span>C. (5x-8)(x-2)</span>
3 0
4 years ago
Find 2/5 divided 1/8 simplest form
Mekhanik [1.2K]

Answer: 3.2

Step-by-step explanation: (2/5)/(1/8)=(2/5)*8= 16/5=3 1/5=3.2

8 0
3 years ago
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