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faust18 [17]
3 years ago
7

Point J (-4, -6) and point K (4, 4) are located on a coordinate grid. Which measurement is closest to the distance between point

J and point K in units?
Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

The points are sqrt(164) or 2sqrt(41) units apart.

Explanation:

You didn't provide the options in your question. But to find the distance, you need to use the distance formula.

d=sqrt((y2-y1)^2 + (x2-x1)^2)

d is the distance, and (x1, y1) and (x2, y2) are the points.

Use point J (-4,-6) for (x1,y1) and point K (4,4) for (x2, y2).

d=sqrt((4-(-6))^2 + (4-(-4))^2)

 =sqrt(10^2 + 8^2)

 =sqrt(100+64)

 =sqrt(164)=2sqrt(41)

You can compare this to the answer options and find the closest. Hope I could help! :)

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∑ Hey, jillianwagler ⊃

Answer:

\left(x+8\right)\left(x-8\right)

Step-by-step explanation:

<u><em>⇒ Given info:</em></u>

<em>Factor completely </em>x^2 -64

<u><em>⇒ Solution:</em></u>

<em>Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.</em>

<em />=x^2-8^2

Applying difference of two squares formula: x^2-y^2=\left(x+y\right)\left(x-y\right)

=x^2-8^2=\left(x+8\right)\left(x-8\right)\\

=\left(x+8\right)\left(x-8\right)

Answer~: \left(x+8\right)\left(x-8\right)

<u><em>xcookiex12</em></u>

<em>8/19/2022</em>

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