Answer:
The total mass of the reactants is <u>equal to </u> the total mass of the products in a chemical reaction.
Explanation:
Answer:

Explanation:
The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

Where "n" is the <u>number of carbons</u>, in this case "18", so:

We also have to calculate the amount of Acetyl-Coa produced:

Now, we have to keep in mind that in each round in the beta-oxidation we will have the <u>production of 1
and 1
</u>. So, if we have 8 rounds we will have 8
and 8
.
Finally, for the total calculation of ATP. We have to remember the <u>yield for each compound</u>:
-)
-) 
-) 
Now we can do the total calculation:

We have to <u>subtract</u> "2 ATP" molecules that correspond to the <u>activation</u> of the fatty acid, so:

In total, we will have 128 ATP.
I hope it helps!
in these options not any Element are liquid at 1000k i think you type wrong in first option It is Hg not Ag and Hg is liquid at 1000 k
Answer:
3.10×10¯⁵ ft³.
Explanation:
The following data were obtained from the question:
Density (D) of lead = 11.4 g/cm³
Mass (m) of lead = 10 g
Volume (V) of lead =.?
Density (D) = mass (m) / Volume (V)
D = m/V
11.4 = 10 / V
Cross multiply
11.4 × V = 10
Divide both side by 11.4
V = 10 / 11.4
V = 0.877 cm³
Finally, we shall convert 0.877 cm³ to ft³. This can be obtained as follow:
1 cm³ = 3.531×10¯⁵ ft³
Therefore,
0.877 cm³ = 0.877 cm³ × 3.531×10¯⁵ ft³ /1 cm³
0.877 cm³ = 3.10×10¯⁵ ft³
Thus, 0.877 cm³ is equivalent to 3.10×10¯⁵ ft³.
Therefore, the volume of the lead in ft³ is 3.10×10¯⁵ ft³.
Answer:
The answer to your question is: SiCl₄
Explanation:
Data
amount of Si 1.71 g
amount of Cl 8.63 g
MW Si = 28 g
MW Cl = 35.5
Process (rule of three)
For Si For Cl
28 g of Si ------------------ 1 mol 35.5 g of Cl --------------- 1 mol
1.71g of Si --------------- x 8.63 g of Cl -------------- x
x = 1.71 x 1 / 28 = 0.06 mol x = 8.63 x 1 / 35.5 = 0.24 mol
Now, divide both results by the lowest of them.
Si = 0.06 mol / 0.06 = 1 molecule of Si Cl = 0.24 / 0.06 = 4 molecules of Cl
Finally
Si₁ Cl₄ or SiCl₄