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bekas [8.4K]
3 years ago
11

Which of the following accurately describes a Brønsted-Lowry acid?

Chemistry
2 answers:
luda_lava [24]3 years ago
4 0

Answer:

B. A Brønsted-Lowry acid donates a proton and has a matching conjugate base.

Explanation:

Here's HA is bronsted acid and its conjugate base pair is A-.

Aleksandr [31]3 years ago
4 0

Answer:

Explanation:

The actual answer is B. The equation has an acid on one side and a base on the other. The acid donates a proton. Donates means gives up the equivalent of a proton.

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The total mass of the reactants is ________ the total mass of the products in a chemical reaction.
jonny [76]

Answer:

The total mass of the reactants is <u>equal to </u>  the total mass of the products in a chemical reaction.

Explanation:

5 0
3 years ago
If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m
Nadusha1986 [10]

Answer:

128~ATP

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

Number~of~Rounds=\frac{n}{2}-1

Where "n" is the <u>number of carbons</u>, in this case "18", so:

Number~of~Rounds=\frac{18}{2}-1~=~8

We also have to calculate the amount of Acetyl-Coa produced:

Number~of~Acetyl-Coa=\frac{18}{2}~=~9

Now, we have to keep in mind that in each round in the beta-oxidation we will have the <u>production of 1 FADH_2 and 1 NADH</u>. So, if we have 8 rounds we will have 8 FADH_2 and 8 NADH.

Finally, for the total calculation of ATP. We have to remember the <u>yield for each compound</u>:

-) 1~FADH_2~=~2~ATP

-) 1~NADH~=~3~ATP

-) Acetyl~CoA~=~10~ATP

Now we can do the total calculation:

(8*2)~+~(8*3)~+~(9*10)=130~ATP

We have to <u>subtract</u>  "2 ATP" molecules that correspond to the <u>activation</u> of the fatty acid, so:

130-2=128~ATP

In total, we will have 128 ATP.

I hope it helps!

6 0
3 years ago
Which element is a liquid at 1000 k <br><br> 1.Ag<br> 2.Al<br> 3.Ca<br> 4.Ni
AlexFokin [52]

in these options not any Element are liquid at 1000k i think you type wrong in first option It is Hg not Ag and Hg is liquid at 1000 k

7 0
3 years ago
Read 2 more answers
The density of lead is 11.4g/cm3. What volume, in ft3, would be occupied by 10.0 g of lead?
yawa3891 [41]

Answer:

3.10×10¯⁵ ft³.

Explanation:

The following data were obtained from the question:

Density (D) of lead = 11.4 g/cm³

Mass (m) of lead = 10 g

Volume (V) of lead =.?

Density (D) = mass (m) / Volume (V)

D = m/V

11.4 = 10 / V

Cross multiply

11.4 × V = 10

Divide both side by 11.4

V = 10 / 11.4

V = 0.877 cm³

Finally, we shall convert 0.877 cm³ to ft³. This can be obtained as follow:

1 cm³ = 3.531×10¯⁵ ft³

Therefore,

0.877 cm³ = 0.877 cm³ × 3.531×10¯⁵ ft³ /1 cm³

0.877 cm³ = 3.10×10¯⁵ ft³

Thus, 0.877 cm³ is equivalent to 3.10×10¯⁵ ft³.

Therefore, the volume of the lead in ft³ is 3.10×10¯⁵ ft³.

7 0
3 years ago
Determine the empirical formula of a compound containing 1.71 g of silicon and 8.63 g of chlorine.
Basile [38]

Answer:

The answer to your question is: SiCl₄

Explanation:

Data

amount of Si      1.71 g

amount of Cl     8.63 g

MW Si = 28 g

MW Cl = 35.5

Process (rule of three)

For Si                                                        For Cl

        28 g of Si ------------------ 1 mol                      35.5 g of Cl --------------- 1 mol

          1.71g of Si  ---------------   x                              8.63 g of Cl --------------  x

         x = 1.71 x 1 / 28 = 0.06 mol                          x = 8.63 x 1 / 35.5 = 0.24 mol

Now, divide both results by the lowest of them.

Si = 0.06 mol / 0.06 = 1 molecule of Si     Cl = 0.24 / 0.06 = 4 molecules of Cl

Finally

                     Si₁ Cl₄ or SiCl₄

8 0
3 years ago
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