Answer:
The answer to your question is the first choice (H₂)
Explanation:
Process
Look for the electronegativity of the elements of this exercise
a) H₂ = 2.2 - 2.2 = 0
b) NaF = 3.98 - 0.93 = 3.05
c) HBr = 2.96 - 2.2 = 0.76
d) HS⁻ = 2.58 - 2.2 = 0.38
The molecule that has the smallest difference in electronegativity is H₂
Answer:
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Explanation:
We are given the compound: Cs₃PO₄
According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.
Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.
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3 moles of cesium phosphate contains <u>9 moles of cesium.</u>
Answer:
5446.8 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 50 g
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Specific heat capacity (C) = 0.89 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 192.4 – 70
ΔT = 122.4 °C
Finally, we shall determine the heat required to heat up the block of aluminum as follow:
Mass (M) = 50 g
Specific heat capacity (C) = 0.89 J/gºC
Change in temperature (ΔT) = 122.4 °C
Heat (Q) required =?
Q = MCΔT
Q = 50 × 0.89 × 122.4
Q = 5446.8 J
Thus, the heat required to heat up the block of aluminum is 5446.8 J
The answers is 67 don’t ask me I don’t know but trying to get free points