Answer:
What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?
A) 19.6
B) 39.1
C) 19,600
D) 39,100
E) 276
The correct answer to the question is
B) 39.1 grams
Explanation:
To solve the question
The molarity ratio is given by
188 ml of 0.532 M solution of iodide.
Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles
To find the mass, we note that the Number of moles =
from which we have
Mass = Number of moles × molar mass
Where the molar mass of Barium Iodide = 391.136 g/mol
= 0.100016 moles ×391.136 g/mol = 39.12 g
Answer:
a free swimming larval stage in which a parasitic fluke passes from an intermediate host to another intermediate host
Answer:
True
Explanation:
True. If an animal has attributes to it that help it survive better in an environment, it will survive better than its counterparts who do not have this attribute. More survival = More offspring
Answer:
1.1 M
General Formulas and Concepts:
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define variables</u>
1.2 mol KCL
1.1 L of solution
M = unknown
<u>Step 2: Solve for Molarity</u>
- Substitute: M = 1.2 mol/1.1 L
- Evaluate: M = 1.09091
<u>Step 3: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
1.09091 M ≈ 1.1 M