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Nady [450]
3 years ago
13

a certain skin lotion is a fine mixture of water and various oils. this lotion is cloudy and cannot be separated into oil and wa

ter by filtration. moreover, it’s compon do not separate when left standing. what type of mixture is it?
Chemistry
1 answer:
PolarNik [594]3 years ago
3 0

Answer: The skin lotion is a colloidal mixture of water and various oils.

Explanation:

Mixture: Blend of of two or more components which are chemically unreactive to give any product.

Mixture are defined as  of three types:

Solutions : Mixture in which one component is completely distributed in an other component resulting in clear mixture. They cannot be separated into its components on standing or by filtration.

Suspensions: Mixture in which one component is not completely or uniformly distributed in another component.They separate out into layers when kept undisturbed.

Colloids: Mixture in which one component is uniformly distributed in another component but the mixture formed is not clear. The color of mixture appears turbid or cloudy. They cannot get separated by filtration. They also cannot get separated into its components when left standing.

A skin lotion is a fine mixture of water and oils. it is a cloudy mixture and cannot be separated with help of filtration. Also its components also not separates out on standing. All these properties shown by skin lotion is of colloidal mixture.


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PV = nRT

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P = nRT /V

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P = 1 atm

Therefore, H2 has a pressure of 1 atm.

For N2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, N2 has a pressure of 1 atm

For O2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, O2 has a pressure of 1 atm

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Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

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P = 1 atm

Therefore, He has a pressure of 1 atm.

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