I think they all went to the movies equally per month if you simply compare medians? Since in the second chart, they each have a median of 2 times per month, that makes it equal. If you aren’t sure if this is correct, you have to order how many times each person went to the movies, from least to greatest. For example, John’s would be 1,1,1,2,2,2,2,3,3,3,4,5. Then you would start crossing numbers off from each end. First you would cross off 1, then 5, and then 1, and then 4, and keep going until you reach the number in the very middle, which is 2. Do this with all of the other people, and check if everybody has 2 for a median. I believe they do, however it’s always best to check and be safe. Good luck
Assuming the variables are constants, you isolate m. So move am to the left. K-am=emx. Now divide ex. This gives you, m=(K-am/ex)
Answer:
5≤u
Step-by-step explanation:
Put the words and numbers into an equation:
-5u+27≤2
Put all like terms on one side:
27-2≤5u ---> Do you see what I did there? Now you don't have to work with negatives. :)
Simplify:
25≤5u
Solve:
5≤u
:)
Answer:
<h2>
66 different ways </h2>
Step-by-step explanation:
This is a combination question. Combination has to do with selection. For example if r objects are to be selected from n pool of oblects, this can be done in nCr number of ways.
nCr = n!/(n-r)r!
According to the question, if a radio show can only play 10 records out of 12 records available, this can be done in 12C10 number of ways.
12C10 = 12!/(12-10)!10!
= 12!/2!10!
= 12*11*10!/2*10!
= 12*11/2
= 6*11
= 66 different ways
