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3 years ago

Please provide the answer and an explanation why that is the answer.

Mathematics

1 answer:

nata0808 [166]3 years ago

8 0

its true ax +by=c nthe , x and y are variables and A, B, and C are integers.

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Find the second derivative at the point (2,2), given the function below. 2x^4=4y^3

Bogdan [553]

The second derivative at the point (2,2) is 34/9

Explanation:

2x⁴ = 4y³

2x⁴ - 4y³ = 0

We first need to find dy/dx and then d²y/dx²

On differentiating the equation in terms of x

dy/dx = d(2x⁴ - 4y³) / dx

We get,

dy/dx = 2x³/3y²

On differentiating dy/dx we get,

d²y/dx² = 2x²/y² + 8x⁶/9y⁵

$\frac{d^2y}{dx^2} = \frac{2 X 2^2}{2^2} + \frac{8 X 2^6}{9 X 2^5}\\ \\\frac{d^2y}{dx^2} = 2 + \frac{16}{9}\\ \\$

d²y/dx² = 34/9

Therefore, the second derivative at the point (2,2) is 34/9

7 0

3 years ago

Help me with this exercise

Vinil7 [7]

The answer you are looking for is: 
270 $yards^{2}$ 
15*18= 270 
And you have to add the yard square at the end. 
Hope that helps!! 
Have a wonderful day!!

6 0

3 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$

Substitute point (1, -1) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}$

Equate to find h:

$\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}$

Substitute found value of h into one of the equations to find a:

$\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}$

Substitute found values of h and a to find k:

$\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}$

Therefore, the equation of the parabola in vertex form is:

$\implies y=3(x-0)^2-4=3x^2-4$

So the vertex of the parabola is (0, -4)

5 0

2 years ago

Read 2 more answers

Find the values of the missing sides in the parallelogram given.

natta225 [31]

Given:

m∠B = 44°

Let's find the following measures:

m∠A, m∠BCD, m∠CDE

We have:

• m∠A:

Angle A and Angle B are interior angles on same side of a transversal.

The interior angles are supplementary.

Supplementary angles sum up to 180 degrees

Therefore, we have:

m∠A + m∠B = 180

m∠A + 44 = 180

Subtract 44 from both sides:

m∠A + 44 - 44 = 180 - 44

m∠A = 136°

• m,∠,BCD:

m∠BCD = m∠A

Thus, we have:

m∠BCD = 136°

• m∠CDE:

Angle C and angle CDE form a linear pair.

Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.

Thus, we have:

m∠D = m∠B

m∠D = 44°

m∠CDE + m∠D = 180

m∠CDE + 44 = 180

Subract 44 from both sides:

m∠CDE + 44 - 44 = 180 - 44

m∠CDE = 136°

ANSWER:

• m∠A = 136°

•

• m∠BCD = 136°

•

• m∠CDE = 136°

6 0

1 year ago

Please help me im being timed-

miskamm [114]

Simplify square roots
find all the prime factors of the radicand
and group them in pairs
any factor that appears in a pair can be pulled out in front of the radical sign once for ever group of two that can be made.
Hope that help sorry if it doesn't make sense.. :( <3

4 0

2 years ago

Read 2 more answers