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Rainbow [258]
4 years ago
15

How is the answer D 1.5a - 0.5 Please show the working

Mathematics
2 answers:
Anika [276]4 years ago
6 0
1) 1.5a - 0.5 = 0
2) 1.5a - 0.5 + 0.5 = 0 + 0.5
3) 1.5a = 0.5
4) a = 0.5/1.5
5) a = 1/3 or .333
Sloan [31]4 years ago
5 0
Unfortunately, it appears that y ou haven't shared the whole problem.  I have no idea what answer D looks like.

I can tell you that 1.5a - 0.5 can be factored:  0.5(3a - 1)

But I don't know if that's what y ou were supposed to find.
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At 1:00 pm the water level in a pool is 13 inches. At 1:30pm the water level is 18 inches. At 2:30pm the water level is 28 inche
SashulF [63]
From the given question we come to know of certain number of facts and they are:
At 1:00 PM the water level of the pond was = 13 inches
At 1:30 PM the water level of the pond was = 18 inches
At 2:30 PM the water level of the pond was = 28 inches
From the above given facts we can easily find the amount of water changing every half an hour.
Amount of increase in water from 1:00PM to 1:30 PM = (18 - 13) inches
                                                                                       = 5 inches
Amount of increase in water level from 1:30PM to 2:30PM = (28 -18) inches
                                                                                             = 10 inches
From the above two deductions we can come to the conclusion the the constant rate of change in water level is 5 inches for every half an hour.
4 0
3 years ago
Read 2 more answers
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
3 years ago
If two angles of a triangle each measure 50 degrees, then what is the measure of the third angle of the triangle? Complete the s
xxTIMURxx [149]

Answer: 80

Step-by-step explanation:

Triangles equal 180 therefore 50+50=100 and 180-80=80

3 0
3 years ago
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A farmer has a crop of 2,000 orange trees at the beginning of this year. Each year, the farmer plans to plant 250 new trees. Ass
lawyer [7]

Answer:

y=250x+2000

Step-by-step explanation:

The farmer starts with 2000 trees and adds 250 each year.

Year 0   2000

Year 1   2000 + 250 = 2000+ 1(250)

Year 2   2000 + 250 +250 = 2000 + 2(250)

Year 3   2000 + 250 + 250 + 250 = 2000 + 3(250)

Year 4   2000 + 250 + 250 + 250 + 250 = 2000 + 4 (250)

.....

Year X   2000 + 250x

5 0
4 years ago
In ΔLMN, n = 910 inches, ∠L=64° and ∠M=31°. Find the length of l, to the nearest 10th of an inch​
mr_godi [17]

Answer:

821

Step-by-step explanation:

8 0
3 years ago
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