Answer:
λ = 3.33 m
Explanation:
<u><em>Given:</em></u>
Frequency = f = 9 × 10⁷ Hz
Speed = v = 3 × 10⁸ m/s
<u><em>Required:</em></u>
Wavelength = λ = ?
<u><em>Formula:</em></u>
v = fλ
<u><em>Solution:</em></u>
<em>Putting the givens in the formula</em>
v = fλ
λ = 
λ = 
λ = 0.33 × 10¹
λ = 3.33 m
On the change in potential energy
Answer:
If you add the 2 velocity vectors you get the velocity of the third vector which is the (change in) velocity of the cue ball after striking the cushion
V * 2 * cos 45 = 4 * cos 45 = 2.83 m/s
Answer:
(a) a = - 201.8 m/s²
(b) s = 197.77 m
Explanation:
(a)
The acceleration can be found by using 1st equation of motion:
Vf = Vi + at
a = (Vf - Vi)/t
where,
a = acceleration = ?
Vf = Final Velocity = 0 m/s (Since it is finally brought to rest)
Vi = Initial Velocity = (632 mi/h)(1609.34 m/ 1 mi)(1 h/ 3600 s) = 282.53 m/s
t = time = 1.4 s
Therefore,
a = (0 m/s - 282.53 m/s)/1.4 s
<u>a = - 201.8 m/s²</u>
<u></u>
(b)
For the distance traveled, we can use 2nd equation of motion:
s = Vi t + (0.5)at²
where,
s = distance traveled = ?
Therefore,
s = (282.53 m/s)(1.4 s) + (0.5)(- 201.8 m/s²)(1.4 s)²
s = 395.54 m - 197.77 m
<u>s = 197.77 m</u>