Answer:
The magnitude of force must you apply to hold the platform in this position = 888.89 N
Explanation:
Given that :
Workdone (W) = 80.0 J
length x = 0.180 m
The equation for this work done by the spring is expressed as:

Making the spring constant
the subject of the formula; we have:

Substituting our given values, we have:


The magnitude of the force that must be apply to the hold platform in this position is given by the formula :


F = 888.89 N
Answer:
(a) 1000 N/C
Explanation:
Kinetic energy of electron, K = 1.6 x 10^-17 J
distance, d = 10 cm = 0.1 m
Let the potential difference is V and the electric field is E.
(a) The relation between the kinetic energy and the potential difference is
K = e V
V = K / e
Where, e be the electronic charge = 1.6 x 10^-19 C
V = 
V = 100 V
The relation between the electric field and the potential difference is given by
V = E x d
100 = E x 0.1
E = 1000 N/C
(b) The force acting on the electron, F = q E
where q be the charge on electron
So, F = -e x E
It means the direction of electric field and the force are both opposite to each other.
The direction of electric field and the force on electron is shown in the diagram.
Answer:
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
Explanation:
Inelastic Collision
Given data
mass of glider A m1= 0.125kg
initial velocity u1=0
final velocity v1= 0.600 m/s
mass of glider B m2= 0.375kg
initial velocity u2=0
final velocity v2=?
We know that the expression for the conservation of momentum is given as
m1u1+m2u2=m1v1+m2v2
since u1=u2=u=0m/s
u(m1+m2)=m1v1+m2v2
substituting we have
0(0.125+0.0375)=0.125*0.6+0.375*v2
0=0.075+0.375v2
0.375v2=-0.075
v2=-0.075/0.375
v2=-0.2m/s
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
Answer:
I would say the answer is the wave of 21.000Hz
Explanation:
Because it has more frequency, and as more frequency you add, the time or longer period also increases.
Power is the energy transferred or "WORK DONE" in one second