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andreev551 [17]
2 years ago
13

How many molecules are there in a 1.43 mole sample of H2O2?

Chemistry
1 answer:
SIZIF [17.4K]2 years ago
5 0
One mole of hydrogen peroxide contains 6.02 x 10^23 molecules of hydrogen peroxide. And each molecule contains 4 atoms, so the answer is 4 x 6.02 x 10^23.
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Which list of elements consists of a metal, a metalloid, and a nonmetal?
Anna007 [38]
C. Sn (tin) is a metal, Si (silicon) is a metalloid, and C (carbon) is a nonmetal
4 0
3 years ago
Read 2 more answers
Define atomic numberand mass number. Which can vary without changing the identity of the element?
Volgvan

Explanation:

Atomic number is defined as the number of an element which represents total number of protons.

When an atom is neutral then it means it contains same number of protons and electrons.

On the other hand, atomic mass is defined as the sum of total number of protons and neutrons present in an atom.

Protons of every element remains fixed because it shows the identity of each element but if we change the number of neutrons then also identity of the atom will remain fixed. This is because changing the number of neutrons will not show any change in number of protons.

For example, ^{2}_{1}H and ^{3}_{1}H are isotopes of hydrogen and they have same number of protons but different number of neutrons.

Thus, we can conclude that number of neutrons can vary without changing the identity of the element.

8 0
3 years ago
M=10,V=2 What is the density
Sever21 [200]

Answer:

Density (ρ) = 5 kilogram/cubic meter

Explanation:

Steps:

ρ =  

m

V

=  

10 kilogram

2 cubic meter

=  5 kilogram/cubic meter

4 0
2 years ago
A 72.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by a
Aliun [14]

Answer: 0.20 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.40 M

V_1 = volume of stock solution = 72.0 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = 248 ml

1.40\times 72.0=m\times 248

m=0.41M

Now 124 mL portion of this prepared solution is diluted by adding 133 mL of water.

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.41 M

V_1 = volume of stock solution = 124 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = (124 +133) ml = 257 ml

0.41\times 124=m\times 257

m=0.20M

Thus the final concentration of the solution is 0.20 M.

8 0
3 years ago
2. A 2.5 mol SAMPLE OF OXYGEN GAS (O2) INCREASES TO 3.2 mol
lana [24]

696.32 mmHg is the final pressure of the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.

Given data:

P_1 = 720 mmHg              

P_2 = ?

n_1 = 2.5 mol                

n_2 = 3.2 mol

V_1 = 34 L            

V_2 = 45 L

Formula

Combined gas law

\frac{P_1 V_1}{n_1}  = \frac{P_2 V_2}{n_2}

P_2 = 696.32 mmHg

Hence, 696.32 mmHg is the final pressure of the gas.

Learn more about an ideal gas equation here:

brainly.com/question/19251972

#SPJ1

6 0
2 years ago
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