1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
S_A_V [24]
3 years ago
8

In

Chemistry
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

V =  33.62 L

Explanation:

Given data:

Volume = ?

Number of moles of oxygen = 1.5 mol

Temperature = 273 K

Pressure = 1 atm

Solution:

Standard pressure = 1 atm

Standard temperature = 273 K

PV = nRT

V = nRT/ P

V = 1.5 mol × 0.0821 atm. L. K⁻¹. mol⁻¹ ×  273 k / 1 atm

V = 33.62 L. atm// 1 atm

V =  33.62 L

You might be interested in
A student does an experiment to determine the molar solubility of lead(II) bromide. She constructs a voltaic cell at 298 K consi
attashe74 [19]

Answer:

The molar solubility of lead bromide at 298K is 0.010 mol/L.

Explanation:

In order to solve this problem, we need to use the Nernst Equaiton:

E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}

E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.

At equilibrium, E = 0, therefore:

E^{o}  = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] =  log[ox] -  \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] -  \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 -  \frac{2x5.45x10^{-2}  }{0.0591}}\\\\

[red] = 0.010 M

The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.

7 0
3 years ago
A radioactive sample has a half-life of 5 hours. What fraction of the sample will be left after 15 hours?​
DedPeter [7]

Explanation:

hiiiii beautiful.........

6 0
3 years ago
A geochemist in the field takes a 46.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
inysia [295]

Answer:

The solubility of the mineral compound X in the water sample is 0.0189 g/mL.

Explanation:

Step 1: Given data

The volume of water sample = 46.0 mL.

The weight of the mineral compound X after evaporation, drying, and washing = 0.87 g.

Step 2: Calculate the solubility of X in water

46.00 mL of water sample contains 0.87 g of the mineral compound X.

To calulate how many grams of the mineral compound  1.0 mL  of water sample contains:

0.87 g/46.0 mL = 0.0189 g.

This means the solubility of the mineral compound X in the water sample is 0.0189 g/mL.

3 0
3 years ago
Describe at least three ways our understanding of the atom has changed overtime?
myrzilka [38]

Answer:

multitide of uses (drinking, cleaning, cooking, transportation). Without water we would not survive. -Lead atoms bond together and they make up the lead that we use as a pencil. -Copper atoms, aluminum atoms, nickel atoms, etc., all make up metal which is used for a variety of things in everyday life.

Explanation:

7 0
3 years ago
How is a pair of molecular orbitals formed?
Montano1993 [528]
When two atoms combine, the overlap of their atomic orbitals produces molecular orbitals. 
3 0
3 years ago
Read 2 more answers
Other questions:
  • How is current transferred from the moving armature to the rest of the circuit in an alternating current generator
    5·1 answer
  • Given the stretching frequencies for the C–H bonds shown in green, arrange the corresponding bonds in order of increasing streng
    8·2 answers
  • Compound A has molecular formula C7H15Br. Treatment of compound
    6·1 answer
  • What must occur ??????
    10·1 answer
  • Ammonium hydrogen sulfide NH4HS(s) decomposes on heating according to the reaction NH4HS(s) ↔ NH3(g) + H2S(g) At 25 °C the equil
    9·2 answers
  • Why are chromosomes not always visible?
    7·1 answer
  • II. Enumerate the following.
    10·1 answer
  • Determine the Concentration of the Unknown Strong Acid
    10·1 answer
  • Look at the CHEMICAL EQUATION below...
    13·1 answer
  • The decomposition of HI(g) is a second order reaction.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!