All categories

3 years ago

In

Chemistry

1 answer:

Lelechka [254]3 years ago

4 0

Answer:

V = 33.62 L

Explanation:

Given data:

Volume = ?

Number of moles of oxygen = 1.5 mol

Temperature = 273 K

Pressure = 1 atm

Solution:

Standard pressure = 1 atm

Standard temperature = 273 K

PV = nRT

V = nRT/ P

V = 1.5 mol × 0.0821 atm. L. K⁻¹. mol⁻¹ × 273 k / 1 atm

V = 33.62 L. atm// 1 atm

V = 33.62 L

You might be interested in

A sample of seawater has 0.075 g of sodium chloride per mL of solution. How many moles of sodium chloride are there per liter of

amm1812

Answer:

1.28 mol

Explanation:

mole = mass/molar mass

n = v/v/cm³

mass = 0. 075g

v = 1dm³ =1000cm³

n= m/MV=0.075/58.44(1000)

n =1.28 mol

4 0

4 years ago

The substances that are produced after the chemical reaction are called the ___

sertanlavr [38]

Answer:

Products

Explanation:

During a chemical reaction, there are the reactants (left side), and the products (right side).

6 0

3 years ago

Read 2 more answers

Generally speaking, elements with high electronegativities are 1. nonmetals. 2. likely to form anions (except the noble gases).

satela [25.4K]

Answer:

1. Nonmetals.

2. Likely to form anions (except the noble gases).

3. All of these

4. Easily reduced (except the noble gases).

Explanation:

Elements with high electronegativities are found towards the upper right corner of the Periodic Table. Thus, they have all the above properties.

4 0

3 years ago

Match the terms with their correct definition:

geniusboy [140]

7 0

3 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

3 years ago