Answer:
9.85mL
Explanation:
First, let us write a balanced equation for the reaction. This is illustrated below:
Ca(OH)2 + 2HNO3 —> Ca(NO3)2 + 2H2O
From the balanced equation above,
nA (mole of the acid) = 2
nB (mole of the base) = 1
Data obtained from the question include:
Vb (volume of the base) =?
Mb (Molarity of base) = 0.155 M
Va (volume of the acid) = 28.8 mL
Ma (Molarity of acid) = 0.106 M
Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:
MaVa/MbVb = nA/nB
0.106 x 28.8 / 0.155 x Vb = 2/1
Cross multiply to express in linear form as shown below:
2 x 0.155 x Vb = 0.106 x 28.8
Divide both side by 2 x 0.155
Vb = (0.106 x 28.8) / (2 x 0.155)
Vb = 9.85mL
Therefore, the Volume of calcium hydroxide is 9.85mL
