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olga55 [171]
3 years ago
13

If hydrofluoric acid is a stronger acid than acetic acid, which statement is most likely true?

Chemistry
1 answer:
Alchen [17]3 years ago
4 0

Answer: The statement conjugate base of hydrofluoric acid is weaker than that of acetic acid is most likely true.

Explanation:

A strong acid upon dissociation gives a weak conjugate base. This can also be said as stronger is the acid, weaker will be its conjugate base or vice-versa.

Hydrofluoric acid is a strong base as it dissociates completely when dissolved in water.

For example, HF \rightleftharpoons H^{+} + F^{-}

The conjugate base is F^{-} which is a weak base.

Acetic acid is a weak acid as it dissociates partially when dissolved in water. So, the conjugate base of acetic acid is a strong base.

CH_{3}COOH \rightarrow CH_{3}COO^{-} + H^{+}

Thus, we can conclude that the statement conjugate base of hydrofluoric acid is weaker than that of acetic acid is most likely true.

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4. Find the pH at each of the following points in the titration of 25 mL of 0.3 M HF with 0.3 M NaOH. The Ka value is 6.6x10-4 a
yawa3891 [41]

Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

Initial0.3 M-0 M0 MChange- X-+ X+XEquilibrium0.3 - X-X MX M

Writing the information from the ICE Table in Equation form yields

6.6×10−4=x20.3−x6.6×10−4=x20.3−x

Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

Now this information is plugged into the quadratic formula to give

x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

6 0
3 years ago
If 1,079.75 Joules of heat are added to 77.75 grams of water, by how many degrees Celsius would the water increase? Assume water
djyliett [7]

Answer:

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of  water will increase

\Delta T=3.32 C^{0}

Explanation:

q = mC\Delta T

Here , q = heat added / removed from the substance

m  = mass of the substance taken

\Delta T = Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

4.18 J/gC^{0}

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

q = mC\Delta T

on transposing ,

\Delta T=\frac{q}{mC}

\Delta T=\frac{1079.75}{77.75\times 4.18}

\Delta T=3.32 C^{0}

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3 years ago
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Answer:

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  • 2. Shape: the sheet can be formed into a paper ball or any other shape (using origami for example).

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Explanation:

<em>Physical changes</em> do not change the chemical properties. They do not transform the compounds that form the substances. They do not break and or form chemical bonds.

When you change the form, the state (solid, liquid or gas), the color, you are just changing physical properties.

Only chemical changes change the compounds that form the substance. For instance, if you burn the <em>sheet of paper</em>, then you are causing a chemical change because the organic matter in the paper will react with oxygen forming CO₂ and water, but by cutting, folding, smashing, or coloring with crayons, the compounds in the<em> sheet of paper</em> do not change.

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Answer:

He was an American statesman, politician, legal scholar. military commander, lawyer, banker and economist.

7 0
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2.) carbon + oxygen → carbon dioxide 
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