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olga55 [171]
3 years ago
13

If hydrofluoric acid is a stronger acid than acetic acid, which statement is most likely true?

Chemistry
1 answer:
Alchen [17]3 years ago
4 0

Answer: The statement conjugate base of hydrofluoric acid is weaker than that of acetic acid is most likely true.

Explanation:

A strong acid upon dissociation gives a weak conjugate base. This can also be said as stronger is the acid, weaker will be its conjugate base or vice-versa.

Hydrofluoric acid is a strong base as it dissociates completely when dissolved in water.

For example, HF \rightleftharpoons H^{+} + F^{-}

The conjugate base is F^{-} which is a weak base.

Acetic acid is a weak acid as it dissociates partially when dissolved in water. So, the conjugate base of acetic acid is a strong base.

CH_{3}COOH \rightarrow CH_{3}COO^{-} + H^{+}

Thus, we can conclude that the statement conjugate base of hydrofluoric acid is weaker than that of acetic acid is most likely true.

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Frank has a paper clip. It has a mass of 9g and a volume of 3cm3. What is its density?
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ANSWER(S):

p= 3 g/cm³

EXPLANATION(S):

density formula: p= m/V; p= p, m= 9 g, V= 3
p= (9)/(3)
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p= 3 g/cm³
5 0
3 years ago
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Vanillin, C8H8O3, is the active ingredient in vanilla flavoring. It contains a six-membered aromatic ring with an aldehyde group
dlinn [17]

Answer:

The answer is in the picture attached

Explanation:

A six-membered aromatic ring is one of the most common structures in natural compounds.

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I hope it helps!

3 0
3 years ago
12 the products of the neutralization reaction between hydrochloric acid and magnesium hydroxide are
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5 0
3 years ago
Aluminum metal and manganese (IV) oxide react to produce aluminum oxide and manganese metal. What mass of manganese (IV) oxide r
gayaneshka [121]

Answer: 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

Explanation:

The balanced chemical equation is:

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To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of manganese = \frac{1.12\times 1000g}{55g/mol}=20.4mol

According to stoichiometry :

3 moles of Mn is produced by = 3 moles of MnO_2

Thus 20.4 moles of Mn is produced by =\frac{3}{3}\times 20.4=20.4moles  of MnO_2

Mass of MnO_2=moles\times {\text {Molar mass}}=20.4moles\times 86.9g/mol=1773g=1.773kg    (1kg=1000g)

Thus 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

6 0
3 years ago
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