Easy Mole Conversion: How many grams are in 2.00 moles of cobalt (I) hydroxide?
1 answer:
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C. Aluminum (Al) oxidized, zinc (Zn) reduced
<h3>Further explanation</h3>Given
Metals that undergo oxidation and reduction
Required
A galvanic cell
Solution
The condition for voltaic cells is that they can react spontaneously, indicated by a positive cell potential.
or:
E ° cell = E ° reduction-E ° oxidation
For the reaction to occur spontaneously (so that it E cell is positive), the E° anode must be less than the E°cathode
If we look at the voltaic series:
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>
The standard potential value(E°) from left to right in the voltaic series will be greater, so that the metal undergoing an oxidation reaction (acting as an anode) must be located to the left of the reduced metal (as a cathode)
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From the available answer choices, oxidized Al (anode) and reduced Zn (cathode) are voltaic/galvanic cells.
The question requires us to use the dilution formula , where
and
are the stock concentration and volume respectively, then
and
are the dilute concentration and volume respectively.
a. = 1.5 M KCI,
=0.20M KCl,
=250ml KCl
b.
To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.