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spin [16.1K]
3 years ago
14

Easy Mole Conversion: How many grams are in 2.00 moles of cobalt (I) hydroxide?

Chemistry
1 answer:
Mila [183]3 years ago
3 0

Answer:

Mass = 185.896 g

Explanation:

Given data:

Mass in gram = ?

Number of moles = 2.00 mol

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of cobalt (I) hydroxide =92.948 g/mol

by putting the values,

2.00 mol = Mass/92.948 g/mol

Mass = 2.00 mol × 92.948 g/mol

Mass = 185.896 g

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3 years ago
Determine the molecular formula for the compound with a molar mass of 46.08 g/mol and the following percent compostion:
kramer

Answer:

      \large\boxed{\large\boxed{CH_6N_2}}

Explanation:

<u><em>1. First determine the empirical formula.</em></u>

a) Base: 100 g of compound

             mass       atomic mass      number of moles

                g                g/mol                    mol

C           26.06            12.011             26.06/12.011   = 2.17

H           13.13              1.008              13.13/1.008    =  13.03

N           60.81             14.007            60.81/14.007 = 4.34

b) Divide every number of moles by the smallest number: 2.17

mass       number of moles        proportion

C                  2.17/2.17                         1

H               13.03/2.17                         6

N                4.34/2.17                          2

c) Empirical formula

      CH_6N_2

d) Mass of the empirical formula

      1\times 12.011g/mol6+6\times 1.008g/mol+2\times 14.007g/mol=46.07g/mol

<u><em>2. Molecular formula</em></u>

Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:

                   CH_6N_2

6 0
3 years ago
A pumpkin has a volume of 10 cm and a mass of 8 g. what is the density of the pumpkin​
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Answer: 0.8g/cm^3

Explanation:

In seeing your problem, I see an issue with your units for centimeter. The volume is in the third dimension, so we use cm^3 every single time for the volume. That way, we can arrive to the correct density (in g/cm^3)

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