Hi,
Homogeneous mixture 2
Heterogeneous 3
Mixture 1
Solution 5
Compound 4
Answer:- 14.0 moles of hydrogen present in 2.00 moles of ![[tex]C_6H_7N](https://tex.z-dn.net/?f=%20%5Btex%5DC_6H_7N)
.
Solution:- We have been given with 2.00 moles of 
and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .
This is the balanced eq
N2 + 3H2 -> 2NH3
first you need to find mole of N2 by using
mol = mass ÷ molar mass.
mol N2= 20g ÷ (14.01×2)g/mol
=0.7138mol
then look at the coefficient between H2 and NH3.
it is N2:NH3
1:2
0.7138:0.7138×2
0.7138:1.4276 moles
moles of NH3 = 1.4276 moles
Answer:
An ecosystem is a community of species.
Explanation:
i hope this helps i tried^^
Answer:
<h3>2Al+ Fe2O3 gives 2Fe + Al2O3. The given reaction is a redox reaction. As oxidation and reduction are taking place simultaneously.</h3>
Explanation:
like this...Identify oxidation and reduction with their agents:
<h3>•2Al+ Fe2O3 →2Fe + Al2O3</h3>
<h3>•Fe2O3 is reduced to Fe whereas Al is oxidized to Al2O3</h3>
<h3>In the above reaction:</h3>
<h3>Oxidizing agent:Fe2O3</h3>
<h3>Reducing agent:Al</h3>
I hope it's help you (◠‿・)—☆
