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3 years ago

Slobs for x, pls help asap ! thanks

Mathematics

2 answers:

makkiz [27]3 years ago

8 0

Answer:

$-6x+14$

$-6x$

Add,

$-6x$

Divide both sides by 6

$\frac{6x}{6}>\frac{42}{6}$

$x>7$

$3x+28\leq 25$

Subtract both sides by 28

$3x\le \:-3$

Now, divide both sides by 3

$x\le \:-1$

Answer:- $x\leq -1\: or \: x>7$

<u>OAmalOHopeO</u>

ad-work [718]3 years ago

6 0

Answer:

Option D, there are no solutions

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Read 2 more answers

Set up an algebraic equation and then solve.

svetlana [45]

Answer:

Width: 6

Length: 20

Step-by-step explanation:

So the area of a rectangle can be defined as: $A=wl$ where w=width and l=length.

In this case we don't know what the length is, so let's just say the length is the variable l, and since the width is 14 units less than the length, we can express it as (l-14). this gives us the equation: $A=l(l-14)=l^2-14l$ . We can solve for l, since we're given the area which is 120. So let's set the equation equal to that: