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2 years ago

Help pls! First to answer gets brainliest

Mathematics

1 answer:

amid [387]2 years ago

7 0

Answer: $3.92
STEOS TO SOLUTION: take $19.62 and divide by 5

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-2/3 minus (-4/6)= <br>

lina2011 [118]

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$- \frac{2}{3} - ( - \frac{4}{6} ) = \\$

$- \frac{2}{3} + \frac{4}{6} = \\$

$- \frac{2}{3} + \frac{2 \times 2}{2 \times 3} = \\$

$- \frac{2}{3} + \frac{2}{3} = 0\\$

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2 years ago

How would you find the volume of the solid in the figure shown above?

Natasha_Volkova [10]

The answer is D and it's pretty simple to do:

$V_{1}=a*b*c\\
V_{2}= \pi r^{2} h\\
V_{3}= \frac{1}{3} \pi r^{2}h$

5 0

2 years ago

Read 2 more answers

What is the coefficient of the term of degree 8 in the polynomial below?

Nesterboy [21]

The correct answer is: [D]: "5 (five)" .
______________________________________________________
<u>Note</u>: The term of "degree 8" is the term with a variable with
an exponent of "8" ; which in this case is " + 5x⁸ ".

The "coefficient" is "5" (five).
______________________________________________________

5 0

2 years ago

For each diagram, describe a translation, rotation, or reflection that takes line ℓ to line ℓ′. Then plot and label A′ and B′, t

lozanna [386]

Hello. I cannot see the images if you show them I’ll answer

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2 years ago

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Given that LM and LN are tangent to the circle and that the measure of angle MLN = 75.86, find the measure of arc MN.

siniylev [52]

we know that

The measure of the external angle is the semidifference of the arcs that it covers

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

Let

x------> minor arc MN

major arc MN=360-x

substitute in the formula above

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x

x=104.14°

therefore

the answer is

the measure of arc MN (minor arc) is 104.14°

7 0

2 years ago