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Mariana [72]
3 years ago
5

The angular acceleration of a wheel is given in rad/s2 by 48 t 3 - 11t 4, where t is in seconds. if the wheel starts from rest a

t t = 0.00 s, when is the next time the wheel is at rest?
Physics
1 answer:
Tpy6a [65]3 years ago
5 0
The answer should be 11 ft
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An important measure of LCD monitors is the time in milliseconds (ms) that it takes to turn a pixel on or off. What is this call
AleksandrR [38]

Answer:

Response Time

Explanation:

The time in milliseconds that LCD monitors takes to turn a pixel on or off is called Response time. A lower response time means that the LCD is able to cut down blurring or Ghosting of images thus producing better quality images.

Response time in general terms is the time interval that a system or a person takes to react to given input or event.

3 0
3 years ago
a hockey player makes a slap shot exerting a constant force of 25.0 N on the puck for 0.16 seconds. With is the magnitude of the
Sav [38]

Impulse = (force) x (time the force is applied)

Impulse = (25 N) x (0.16 sec)

<em>Impulse = 4 Newton-seconds</em>

8 0
3 years ago
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Which of these statements best explains why models are used to study atoms? Atoms of all materials are not the same. Atoms canno
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Answer by YourHope:


Hi! :)


Which of these statements best explains why models are used to study atoms?


Atoms are too small to be examined in detail without a microscope!


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3 0
3 years ago
What would happen if an Asteroid hit earth?
svp [43]

Answer:

There would be tremendous earthquakes and tsunamis, followed by massive volcanism around the impact zone. The ozone layer would be destroyed. The oceans would turn acidic. The Sun would be blotted out, probably for decades.              

Explanation:

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4 0
3 years ago
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harge of uniform density (100 nC/m3) is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical sur
Elden [556K]

Answer:

The magnitude of the electric field is 8.47 N/C

Explanation:

Given;

uniform charge density, λ = 100 nC/m³

inner radii of the cylinder, r =  1.0 mm and 3.0 mm

distance from the symmetry axis, R = 2.0 mm

Volume =\pi (R^2 -r^2)l\\\\Volume =\pi ((2*10^{-3})^2 -(1*10^{-3})^2)l\\\\Volume =\pi (4*10^{-6} - 1*10^{-6})l\\\\Volume = 3*10^{-6} \pi l \ m^3

Area = 2πrl

Area =2π(2 x 10⁻)l

Volume = A x d

d = Volume / Area

d = \frac{V}{A} = \frac{3*10^{-6}*\pi*l}{4\pi *10^{-3} l} = 75 *10^{-5} \ m

the magnitude of the electric field

E = \frac{\lambda *d}{\epsilon_o} = \frac{100*10^{-9} *75*10^{-5}}{8.854*10^{-12}} \\\\E = 8.47 \ N/C

Therefore, the magnitude of the electric field is 8.47 N/C

6 0
3 years ago
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