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AlekseyPX
3 years ago
10

What would happen if an Asteroid hit earth?

Physics
2 answers:
svp [43]3 years ago
4 0

Answer:

There would be tremendous earthquakes and tsunamis, followed by massive volcanism around the impact zone. The ozone layer would be destroyed. The oceans would turn acidic. The Sun would be blotted out, probably for decades.              

Explanation:

    Hope this helps!

Mars2501 [29]3 years ago
4 0

Answer: Well it depends on the size. If the asteroid was the size of a basketball, it would most probably turn to dust by the time it reaches the surface. But, if it was the size of Australia, then most probably everyone would die.

Explanation:

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navik [9.2K]
Hello! 

The kind of gas cloud that is most likely to give birth to stars is a cold, dense gas cloud.

Stars are formed in giant molecular clouds, called "star nurseries". These are regions with molecular Hydrogen, Helium, and little amounts of other elements. These are cold and dense regions, and the gas cloud collapses, forming a protostar. The protostar gradually heats, powering nuclear reactions in its center, which increases the temperature even more and giving birth to a star. 

Have a nice day!
7 0
2 years ago
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Aleksandr [31]

Answer:

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Explanation: because it was last weekend it was in the past so the past tense of assembled must be used

5 0
2 years ago
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asambeis [7]

23 is the right answer.

3 0
3 years ago
While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the
nirvana33 [79]
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7 0
2 years ago
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10) Two students want to use a 12-meter long rope to create standing waves. They first measure the speed at which a single wave
zhannawk [14.2K]

Answer:

To create a second harmonic the rope must vibrate at the frequency of 3 Hz

Explanation:

First we find the fundamental frequency of the rope. The fundamental frequency is the frequency of the rope when it vibrates in only 1 loop. Therefore,

f₁ = v/2L

where,

v = speed of wave = 36 m/s

L = Length of rope = 12 m

f₁ = fundamental frequency

Therefore,

f₁ = (36 m/s)/2(12 m)

f₁ = 1.5 Hz

Now the frequency of nth harmonic is given in general, as:

fn = nf₁

where,

fn = frequency of nth harmonic

n = No. of Harmonic = 2

f₁ = fundamental frequency = 1.5 Hz

Therefore,

f₂ = (2)(1.5 Hz)

<u>f₂ = 3 Hz</u>

5 0
3 years ago
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