Limit as x approaches 0 of. (sin3xsin5x)/x^2

1 answer:

4 0

The limit of the function <span>( sin3x sin5x ) / x^2 as x approaches zero is evaulated by substituting the function by zero. Since the answer is zero / zero which is indeterminate. Using L'hopitals rule, we derive separately the numerator and the denominator. we all know that sin 5x and sin 3x are equal to zero. Upon teh first derivative, the answer is still zero / zero. We derive further until the function has a denominator of 2 and a numerator still equal to zero. Since the answer is now zero/ 2 or zero not zero/zero, the limit then is equal to zero.</span>

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ruslelena [56]

It doesn't have to be called width
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3 0

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MissTica

first is proportional. y is 1 and 1/4 times x

second is not proportional.

reason? divided any y value by its corresponding x value and you'll keep getting 1.25, or 1 and 1/4. and the second one is not proportional because dividing the y values by their corresponding x value will give different answers.

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3 years ago

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Dimas [21]

Answer: 5 1/30

Step-by-step explanation:

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2 years ago

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natka813 [3]

Answer:

Step-by-step explanation:

$2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56$

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