An ideal gas occupies 0.4 m3 at an absolute pressure of 500 kPa. What is the absolute pressure if the volume changes to 0.9 m3 a
1 answer:
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Answer:
Explanation:
In this problem we can use Bohr's atomic model, to deal with the electronic transition, so we can have transitions between two given states.
ΔE = -E₀
Lower state final state energy
Fundamental first excited state ΔE₁ = -2.4 - (-4.7) = 2.3 eV
Fundamental second excited state ΔE₂ = -1.0 - (-4.7) = 3.7 eV
Fundamental third excited state ΔE₃ = -0.3 - (-4.7) = 4.4 eV
As they indicate that there are no electrons in the excited states these are the only possible transitions.
When a wide range of light strikes, the frequencies of these energies are absorbed and observed as black bands (absence of radiation) in the spectrum.
Answer:
Kinetic energy of the electron
Explanation:
It is given that,
Initial speed of an electron, u = 660000 m/s
Final speed of the electron, v = 0 (at rest)
The kinetic energy of an electron is possessed due to the motion of an electron. The mathematical formula for the kinetic energy is given by :
m is the mass of electron
Since,
So, the initial kinetic energy of the electron is 1.23 eV. Hence, this is the required solution.
Answer:
1.117935:1
Explanation:
Since the wires are of the same material, they will have the same resistivity .
The cross-sectional area of the of a wire is given by;
where d is the diameter of the wire.
Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;
Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;
Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;
Given;
We then use equation (1) to fine the ratio of the area to
bearing in mind that
This ratio gives 0.8281. Substituting this into equation (5), we get the following;