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3 years ago

Ram covers distance of zoom in 50 seconds what is his speed

Physics

1 answer:

Reptile [31]3 years ago

7 0

Answer:

speed = distance/time

this is the equation substitute your values and get the answer....btw check you question again..

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Please fast answerrr thank you

Vedmedyk [2.9K]

Answer:

50J

Explanation:

At the top you have(A)

KE_a = O

PE_a = 100J

KE + PE = 100J

At the bottom you have (C)

KE_c= 100J

PE_c=0J

KE+PE = 100J

At point C:

You are at half the height.

We know that at H, PE =100J

PE_c = mgH

At C,

PE_c= mg (H/2) *at half the height

*m and g stay the same

Intuitively, the higher you are, the more potential energy you have.

If you decrease the height by a half, your PE will also decrease

At A:

PE_a / (mg) = H

At B:

PE_b / (mg) = H/2

to also get H on the right hand side, multiply by 2

2 (PE_b/ (mg))= H

2PE_b / (mg) = H

Ok, now that we have set up 2 equations (where H is isolated), find PE at B

AT A = AT B *This way you are saying that H = H (you compare both equations)

PE_a / (mg) = 2x PE_b / (mg)

*mg are the same for both cancel them (you can do that because of the = sign)

PE_a = 2PE_b

We know that PE_a = 100J

100J/2 = PE_b

PE at b = 50J

**FIND KE at b

We know that

KE_b + PE_b is always 100J

100J = 50J + KE_b

KE_b = 50J

4 0

2 years ago

Light is an electromagnetic wave and travels at a speed of 3.00 × 108 m/s. The human eye is most sensitive to yellow-green light

Nimfa-mama [501]

Answer:

$f = 5.95 \times 10^{14} Hz$

Explanation:

As we know that the frequency of the wave is given as

$f = \frac{c}{\lambda}$

here we know that

$c = 3 \times 10^8 m/s$

also we know that

$\lambda = 5.04 \times 10^{-7} m$

now we have

$f = \frac{3 \times 10^8}{5.04 \times 10^{-7}}$

$f = 5.95 \times 10^{14} Hz$

6 0

3 years ago

Someone please help me...

mash [69]

Answer:

1 astronomical unit, or AU, is the average distance from the Earth to the Sun; that's about 150 million km. So, Neptune's average distance from the Sun is 30.1 AU. Its perihelion is 29.8 AU, and it's aphelion is 30.4 AU.

Short Answer: it is 29

Explanation:

sorry if its wrong

3 0

3 years ago

For this situation to demonstrate a balanced force, how much force must Omar apply? (In the picture, Sam is pushing a box to the

11111nata11111 [884]

The answers 10N as it equals it out

3 0

3 years ago

Read 2 more answers

In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.

garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

$\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...$

Find the equivalent resistance of the right branch of the circuit:

$R_{eq} = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms$

$\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411$

6 0

2 years ago

Ram covers distance of zoom in 50 seconds what is his speed​

Ram covers distance of zoom in 50 seconds what is his speed