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zmey [24]
3 years ago
11

A snowboarder goes down the hill with a slope of 28° if friction acts on him as he slides down which of the following is the cor

rect free body diagram for this situation

Physics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

A

Explanation:

All of the frictions are the same, but weight always goes straight down so it can only be A or B. Since they are going down a slope, then the normal force must be sloped. A is the only one out of A and B with a sloped normal force, so it has to be A

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Will each of the following actions increase the distance between the diffraction spots? a) Increase the distance between the scr
diamong [38]

Answer:

A) no

B) no

C) yes

D) no

E) yes

5 0
3 years ago
A woman does 260 J of work to move a table 1.9 m across the floor. What is the magnitude of the force applied by the woman to th
balandron [24]

Answer:136.8N

Explanation:

Work=260joules

Distance=1.9m force=?

Force=work/distance

Force=260/1.9

Force=136.8N

4 0
3 years ago
A bowling ball that has a radius of 11.0 cm and a mass of 5.00 kg rolls without slipping on a level lane at 2.80 rad/s.
NemiM [27]

Answer:

\dfrac{K_t}{K_r}=\dfrac{5}{2}

Explanation:

Given that,

Mass of the bowling ball, m = 5 kg

Radius of the ball, r = 11 cm = 0.11 m

Angular velocity with which the ball rolls, \omega=2.8\ rad/s

To find,

The ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball.

Solution,

The translational kinetic energy of the ball is :

K_t=\dfrac{1}{2}mv^2

K_t=\dfrac{1}{2}m(r\omega)^2

K_t=\dfrac{1}{2}\times 5\times (0.11\times 2.8)^2

The rotational kinetic energy of the ball is :

K_r=\dfrac{1}{2}I \omega^2

K_r=\dfrac{1}{2}\times \dfrac{2}{5}mr^2\times \omega^2

K_r=\dfrac{1}{2}\times \dfrac{2}{5}\times 5\times (0.11)^2\times (2.8)^2

Ratio of translational to the rotational kinetic energy as :

\dfrac{K_t}{K_r}=\dfrac{5}{2}

So, the ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball is 5:2

4 0
3 years ago
Two objects having masses m1 and m2 are connected to each other as shown in the figure and are released from rest. There is no f
tankabanditka [31]

Answer:m_1g

Explanation:

Given

Two masses m_1  and m_2  is released and there is tension T in the string

Suppose a is the acceleration of the system

Therefore from Diagram

For m_1

T-m_1g=m_1a

T=m_1(g+a)------1

for m_2 body

m_2g-T=m_2a

T=m_2(g-a)-------2

From above two Equation it is said that Tension is greater than m_1g and less than m_2g

m_1g

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)
Grace [21]

Answer:

Bernoulli is A

Archimedes is B

Pascal is C

Explanation:

Hope this helps dude

7 0
3 years ago
Read 2 more answers
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