What's $33.99 rounded to the nearest $1, $5 and $10

Mathematics

2 answers:

Reika [66]3 years ago

7 0

Answer:

rounded to the nearest one is $40

Step-by-step explanation:

Galina-37 [17]3 years ago

6 0

Answer:

Nearest $1: $34

Nearest $5: $35

Nearest $10: $30

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A town's population has been growing linearly. In 2003 the population was 47,000. The population has been growing by 1200 people

blsea [12.9K]

Answer:

Step-by-step explanation:

The population in 2003= 47000

Since the population increase by 1200 every year,

in 2004 the population will be 47000+1200

in 2005 the population will be 47000+(1200+1200) which is the same as

47000+2(1200) where 2 is 2 years after 2003,

Therefore the population x years after 2003 is 47000+x(1200).

P= 47000+1200x

b) The population at 2009 which is 6 years after 2003 will be

47000+(1200)*6=47000+7200= 54200

The population at 2009 is 54200,

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3 years ago

The area of a sector with a central angle of 30' is 150'. Determine the approximate length of the diameter.

ioda

Answer:

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3 years ago

Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f

Reil [10]

Answer:

$\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}$

Step-by-step explanation:

The formula of a volume of a square pyramid:

$V=\dfrac{1}{3}a^2h$

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

$\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}$